Tìm x
128-3.(x+4)=23
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( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x ( 45 x128 - 90 x 64) x ( 1995 x 1996 x 1997)
= ( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x ( 5760 - 5760 ) x ( 1995 x 1996 x 1997)
= ( 51 x 52 - 49 x 48 ) x ( 45 x 128 ) x 0 x ( 1995 x 1996 x 1997)
= 0.
#Y/n
\(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
\(\Rightarrow\frac{27}{23}-\frac{4}{23}+\frac{1}{2}-\frac{4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
\(\Rightarrow1+0< x< \frac{7}{3}+\frac{3}{3}\)
\(\Rightarrow1< x< \frac{10}{3}\)
\(\Rightarrow1< x< 3,333333333\)
\(\Rightarrow x\in\left\{2;3\right\}\)
Vậy : ....
ta co : \(\frac{27}{23}+\frac{-4}{23}+\frac{1}{2}+\frac{-4}{8}< x< \frac{7}{3}+\frac{13}{41}+\frac{28}{41}\)
=> \(1< x< \frac{10}{3}\)
vi x la so nguyen => \(1< x\le3\)
con lai ban tu lam
Bài làm :
\(4-\left(27-3\right)=x-\left(13-4\right)-23\)
\(\Leftrightarrow x-\left(13-4\right)-23=4-\left(27-3\right)\)
\(\Leftrightarrow x-9-23=4-24\)
\(\Leftrightarrow x=-20+23+9\)
\(\Leftrightarrow x=12\)
Học tốt
a: =>3(x+4)=115
=>x+4=115/3
hay x=103/3
b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)
\(\Leftrightarrow12x-64=32\)
=>12x=96
hay x=8
c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)
=>(4x+28)x23=120
=>4x+28=120/23
=>4x=-524/23
hay x=-131/23
\(128-3.\left(x+4\right)=23\)
\(128-3x-12=23\)
\(116-3x=23\)
\(3x=116-23\)
\(3x=93\)
\(x=31\)
128 - 3 . ( x + 4 ) = 23
=> 3 . ( x + 4 ) = 128 - 23
=> 3 . ( x + 4 ) = 105
=> x + 4 = 105 : 3
=> x + 4 = 35
=> x = 35 - 4
=> x = 31
Vậy x = 31