9999+9999+999=?
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\(B=1+1+...+1+\dfrac{999...999}{999...991}=20+\dfrac{999...999}{999...991}=...\left(quy.đồng\right)\)
(9+99+999+9999+...........+999.....99999)+100
=(10+100+1000+......+100000.......000)-100
=1111111......1110(99 chu so 1)- 100
\(\frac{1}{9}\),\(\frac{7}{9}\),\(\frac{5}{90}\),\(\frac{7}{900}\),\(\frac{13}{99}\),\(\frac{21}{99}\),\(\frac{32}{99}\),\(\frac{53}{99}\),\(\frac{12}{990}\),\(\frac{46}{9900}\),\(\frac{123}{999}\),\(\frac{456}{999}\),\(\frac{14234}{9999}\),\(\frac{13}{9999}\),\(\frac{7}{99900}\),\(\frac{230}{99900}\),\(\frac{7}{999}\),\(\frac{33}{9999}\),\(\frac{17}{999000}\),\(\frac{230}{999900}\)
999*999*9.999*999.999.999*999*999.999.999=9.969.032.967.062.934.035.697.032.987.001
tớ ghi vậy cho dễ nhìn
9999 + 9999 + 999 = 9999 x 2 + 999 = 19998 + 999
= 20997
9999 + 9999 + 999 = 9999 x 2 + 999
= 19998 + 999
= 20997