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G = -3/10 - 0,125 + -7/10 + 1,125
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NT
1
19 tháng 6 2023
\(-\dfrac{3}{10}-0,125+-\dfrac{7}{10}+1,125\)
`=`\(\left(-\dfrac{7}{10}-\dfrac{3}{10}\right)+\left(-0,125+1,125\right)\)
`= -1 + 1=0`
HQ
Hà Quang Minh
Giáo viên
16 tháng 9 2023
a)
\(\begin{array}{l}\frac{{ - 3}}{{10}} - 0,125 + \frac{{ - 7}}{{10}} + 1,125 \\= \left( {\frac{{ - 3}}{{10}} + \frac{{ - 7}}{{10}}} \right) + \left( {1,125 - 0,125} \right)\\ = - 1 + 1 \\= 0\end{array}\)
b)
\(\begin{array}{l}\frac{{ - 8}}{3}.\frac{2}{{11}} - \frac{8}{3}:\frac{{11}}{9} \\= \frac{8}{3}.\frac{{ - 2}}{{11}} - \frac{8}{3}.\frac{9}{{11}}\\ = \frac{8}{3}.\left( {\frac{{ - 2}}{{11}} - \frac{9}{{11}}} \right)\\ =\frac{{ - 8}}{3}.\frac{-11}{11}\\= \frac{8}{3}.\left( { - 1} \right) \\= \frac{{ - 8}}{3}\end{array}\)
16 tháng 4 2022
\(\dfrac{1}{10}+\dfrac{2}{10}+\dfrac{3}{10}+\dfrac{4}{10}+\dfrac{5}{10}+\dfrac{6}{10}+\dfrac{7}{10}+\dfrac{8}{10}+\dfrac{9}{10}\)
\(=\left(\dfrac{1}{10}+\dfrac{9}{10}\right)+\left(\dfrac{2}{10}+\dfrac{8}{10}\right)+\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{4}{10}+\dfrac{6}{10}\right)+\dfrac{5}{10}\)
\(=1+1+1+1+\dfrac{5}{10}\)
\(=4+\dfrac{5}{10}\)
\(=\dfrac{45}{10}\)
\(13,25:0,5+13,25:0,25+13,25:0,125+13,25\times6\)
\(=13,25:\dfrac{1}{2}+13,25:\dfrac{1}{4}+13,25:\dfrac{1}{8}+13,25\times6\)
\(=13,25\times2+13,25\times4+13,25\times8+13,25\times6\)
\(=13,25\times\left(2+4+8+6\right)\)
\(=13,25\times20\)
\(=265\)
LV
15 tháng 10 2017
\(\frac{7}{5}+\frac{7}{4}-\frac{9}{10}=\frac{63}{20}-\frac{9}{10}=\frac{9}{4}.\)
DD
15 tháng 10 2017
\(\frac{7}{5}+\frac{7}{4}-\frac{9}{10}\)
= \(\frac{28}{20}+\frac{35}{20}-\frac{18}{20}\)
= \(\frac{28+35-18}{20}\)
= \(\frac{45}{20}\)
= \(\frac{9}{4}\)
NT
0
C
5 tháng 3 2023
`a)1/10 + 2/10 + 3/10 + 4/10 + 5/10 + 6/10 + 7/10 + 8/10 + 9/10`
`=(1/10+9/10)+(2/10+8/10)+(3/10+7/10)+(4/10+6/10)+5/10`
`=10/10 + 10/10+10/10+10/10+1/2`
`=1+1+1+1+1/2`
`=2+2+1/2`
`=4+1/2`
`=8/2+1/2`
`=9/2`
__
`13,25:0,5+13,25:0,25+13,25:0,125+13,25×6`
`=13,25×1/(0,5)+13,25×1/(0,25)+13,25×1/(0,125)+13,25×6`
`=13,25×(1/(0,5)+1/(0,25)+1/(0,125)+6)`
`=13,25×(2+4+8+6)`
`=13,25×20`
`=265`
`#QiN`
G = \(\dfrac{-3}{10}\) - 0,125 + \(\dfrac{-7}{10}\) + 1,125
G = -0,3 - 0,125 - 0,7 + 1,125
G = (1,125 - 0,125) - (0,3 + 0,7)
G = 1 - 1
G = 0
G = ( - \dfrac{3}{10} - \dfrac{7}{10} ) + (-0,125 + 1,125)$
$= -1 + 1$
$= 0$