Tính nhanh : 2006x125+1000 / 126x2005-888
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2006x125+1000 / 126x2005-888
= (2005+1)x125+1000 / (125+1)x2005-888
= 2005x125+125+1000 / 125x2005+2005-888
= 2005x125+1125 / 125x2005+1117
= 1125/1117
\(\frac{2016x125+1000}{126x2005-888}\)
\(=\frac{2005x125+(125x11+1000)}{125x2005+(2005-888)}\)
\(=\frac{2005x125+2375}{125x2005+1117}\)
\(=\frac{2005x125+1117+1258}{125x2005+1117}\)
\(=1+\frac{1258}{125x2005+1117}\)
xem lại đề giúp mk nha!
câu 1
125875/125871
câu 2
a) 13/17 < 15/19
b) 12/48 = 9/36
a:2006x125+1000=250750+1000
=251750
b:126x2006-1006=252756-1006
=251750
\(\frac{2006x125+1000}{126x2006-1006}=\frac{2006x125+1000}{125x2006-2006-1006}=\frac{2006x125+1000}{125x2006+1000}=1\)
=\(\frac{2006x125+1000}{125x2006+2006-1006}\)
=\(\frac{2006x125+1000}{125x2006+1000}\)
=1
\(\frac{2006\cdot125+1000}{126\cdot2006-1006}=\frac{2006\cdot\left(126-1\right)+1000}{126\cdot2006-1006}\)
\(=\frac{2006\cdot126-2006+1000}{126\cdot2006-1006}\)
\(=\frac{2006\cdot126-1006}{126\cdot2006-1006}\)
\(=1\)
\(\frac{2006x125+1000}{126x2006-1006}\)
\(=\frac{2006x125+1000}{\left(125+1\right)x2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+1x2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+2006-1006}\)
\(=\frac{2006x125+1000}{125x2006+1000}\)
\(=1\)
2006x125+1000 / 126x2005-888
= (2005+1)x125+1000 / (125+1)x2005-888
= 2005x125+125+1000 / 125x2005+2005-888
= 2005x125+1125 / 125x2005+1117
= 1125/1117