a x 4 + 35 +a x 6 = a x 5 + a x 10
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LX
28 tháng 9 2021
Tìm xx biết: \left(x^{4}\right)^{3}=\dfrac{x^{19}}{x^{6}}(x4)3=x6x19
Trả lời: x=x=
BH
10 tháng 6 2015
1> a) \(\frac{5}{7}x4:\frac{5}{9}=\frac{5}{7}:\frac{5}{9}x4=\frac{5}{7}x\frac{9}{5}x4=\frac{9}{7}x4=\frac{9x4}{7}=\frac{36}{7}\)
\(b,8x\frac{2}{3}:\frac{1}{2}=8x\frac{2}{3}x\frac{2}{1}=8x2x\frac{2}{3}=16x\frac{2}{3}=\frac{32}{3}\)
\(c,6:\frac{3}{5}-\frac{7}{6}x\frac{6}{7}=6x\frac{5}{3}-1=10-1=9\)
\(\frac{21}{5}x\frac{10}{11}+\frac{57}{11}=\frac{42}{11}+\frac{57}{11}=\frac{99}{11}=9\)
2) a) \(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}\)
\(x=\frac{35}{9}x\frac{6}{35}\)
\(x=\frac{2}{3}\)
b) \(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{5}-\frac{1}{6}\right)x10-X=0\)
\(\left(\frac{1}{1}-\frac{1}{6}\right)x10-X=10\)
\(\frac{5}{6}x10-X=0\)
\(X=\frac{5}{6}x10=\frac{25}{3}\)
Đúng nha !!!!
10 tháng 6 2015
1/a/\(\frac{5}{7}\cdot4:\frac{5}{9}=\frac{20}{7}:\frac{5}{9}=\frac{20}{7}\cdot\frac{9}{5}=\frac{36}{7}\)
b/\(8\cdot\frac{2}{3}:\frac{1}{2}=\frac{16}{3}:\frac{1}{2}=\frac{16}{3}\cdot\frac{2}{1}=\frac{32}{3}\)
c/\(6:\frac{3}{5}-\frac{7}{6}\cdot\frac{6}{7}=6\cdot\frac{5}{3}-1=10-1=9\)
2/a/\(\frac{35}{9}:x=\frac{35}{6}\)
\(x=\frac{35}{9}:\frac{35}{6}=\frac{35}{9}\cdot\frac{6}{35}\)
\(x=\frac{2}{3}\)
b/\(\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+\frac{1}{4\cdot5}+\frac{1}{5\cdot6}\right)\cdot10-x=0\)
\(\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}\right)\cdot10-x=0\)
\(\left(\frac{30}{60}+\frac{10}{60}+\frac{5}{60}+\frac{2}{30}\right)\cdot10-x=0\)
\(\frac{47}{60}\cdot10-x=0\)
\(\frac{47}{6}-x=0\)
\(x=\frac{47}{6}-0\)
\(x=\frac{47}{6}\)
PV
Bài 6. Tìm x ϵ N biết
a) (x –15) .15 = 0
b) 32 (x –10 ) = 32
c) ( x – 5)(x – 7) = 0
d) (x – 35).35 = 35
3
18 tháng 12 2021
Bài 1:Tính nhanh:
A,35x6-70x3+35=35
B,10+2+6+7+3+1+8+4+9+5=55
Bài 2:Tìm x:
x+779=4793
x=4793-779
x=4014
x-50374=87493
x=87493+50374
x=137867
xx3=6783
x=6783:3
x=2261
x:3=2967
x=2967x3
x=8901
4 tháng 4 2020
\( a)\\ \dfrac{{3x + 2}}{5} - \dfrac{{4x - 3}}{7} = 4 + \dfrac{{x - 2}}{{35}}\\ \Leftrightarrow 7\left( {3x + 2} \right) - 5\left( {4x - 3} \right) = 140 + x - 2\\ \Leftrightarrow 21x + 14 - 20x + 15 = 140 + x - 2\\ \Leftrightarrow x + 29 = 138 + x\\ \Leftrightarrow 0x = 109\left( {vn} \right)\\ b)\\ \dfrac{{x + 6}}{2} + \dfrac{{2\left( {x + 17} \right)}}{2} + \dfrac{{5\left( {x - 10} \right)}}{6} = 2x + 6\\ \Leftrightarrow 3\left( {x + 6} \right) + 3\left( {2x + 34} \right) + 5x - 50 = 12x - 36\\ \Leftrightarrow 3x + 18 + 6x + 102 + 5x - 50 = 12x - 36\\ \Leftrightarrow 14x + 70 = 12x - 36\\ \Leftrightarrow 2x = - 106\\ \Leftrightarrow x = - 53 \)