Tìm x : ÉT O ÉT
x +2354 =10250 / x - 568 = 5689 / 56140 - x = 6897
56 x \(x\) = 4032 / x : 536 = 86 / 145706 : x = 358
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98775 - 32 x 85
=98775 -2720
=96055
67500 - 24 x 236
= 67500 -5664
=61836
568 + 101598 : 287
= 568 +354
=922
6875 + 980 -180
=7855 -180
=7675
\(\dfrac{2}{5}+\dfrac{3}{10}-\dfrac{1}{2}\)
\(=\dfrac{7}{10}-\dfrac{1}{2}\)
= \(\dfrac{1}{5}\)
\(\dfrac{8}{11}+\dfrac{8}{33}x\dfrac{3}{4}\)
\(=\dfrac{8}{11}+\dfrac{2}{11}\)
\(=\dfrac{10}{11}\)
\(\dfrac{7}{9}x\dfrac{3}{14}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}:\dfrac{5}{8}\)
\(=\dfrac{1}{6}x\dfrac{8}{5}\)
\(=\dfrac{8}{30}\)
\(=\dfrac{4}{15}\)
\(\dfrac{5}{12}-\dfrac{7}{32}:\dfrac{21}{16}\)
\(=\dfrac{5}{12}-\dfrac{7}{32}x\dfrac{16}{21}\)
\(=\dfrac{5}{12}-\dfrac{1}{6}\)
\(=\dfrac{5}{12}-\dfrac{2}{12}\)
\(=\dfrac{3}{12}=\dfrac{1}{4}\)
a: ĐKXĐ: x<>1; x<>-1
b: \(B=\dfrac{x^2+2x+1-x^2+2x-1}{\left(x+1\right)\left(x-1\right)}:\dfrac{2-x^2-x+x-1}{\left(x-1\right)\left(x+1\right)}\)
\(=\dfrac{4x}{-x^2+1}\)
x +2354 =10250
x= 10250 - 2354
x = 7896
x - 568 = 5689
x = 5689 + 568
x = 6257
56140 - x = 6897
x = 56140 - 6897
x = 49243
56 x xx = 4032
x = 4032 : 56
x = 72
x : 536 = 86
x = 86 x 536
x = 46096
145706 : x = 358
x = 145706 : 358
x= 407
x + 2354 = 10250
x = 10250 - 2354 = 7896
x - 568 = 5689
x = 5689 + 568 = 6257
56140 - x = 6897
x = 56140 - 6897 = 49243
56 * x = 4032
x = 4032 : 56 = 72
x : 536 = 86
x = 86 * 536 = 46096
145706 : x = 358
x = 145706 : 358 = 407