tính bằng cách thuận tiện nhất:
a)9.25+9 5x8+9.25
b)14/15 + 3/11 + 1/15 + 3/11 + 10/22
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14/15+3/11+1/15+3/11=10/22
=[14/15+1/15]+[3/11+3/11]
=[14/15+1/15]+[3/11*2]
= 1+6/11
=17/11
a.\(\dfrac{18}{15}+\dfrac{7}{15}+\dfrac{12}{15}=\dfrac{18+7+12}{15}=\dfrac{37}{15}\)
b.\(\dfrac{9}{7}+\dfrac{8}{7}+\dfrac{11}{7}=\dfrac{9+8+11}{7}=\dfrac{28}{7}=4\)
14/15 + 6/11 + 1/15 + 5/11 + 22/11
=(14/15 +1/15)+(6/11 + 5/11 + 22/11)
=1+3
=4
a) \(\frac{14}{15}+\frac{3}{11}+\frac{1}{15}+\frac{3}{11}+\frac{10}{22}\)
\(=\left(\frac{14}{15}+\frac{1}{15}\right)+\left(\frac{3}{11}+\frac{3}{11}\right)+\frac{10}{22}\)
\(=1+1+\frac{10}{22}\)
\(=2+\frac{10}{22}\)
\(=\frac{27}{11}\)
b) 9,25 + 9,25 x 8 + 9,25
= 9,25 x ( 8 + 1 + 1 )
= 9,25 x 10
= 92,5
a) 14/15 + 3/11 + 1/15 + 3/11 + 10/22
= ( 14/15 + 1/15 ) + ( 3/11 + 3/11 + 10/22 )
= 1 + 1
= 2
b) 9,25 + 9,25 x 8 + 9,25
= 9,25 x ( 1 + 8 + 1)
= 9,25 x 10
= 92,5
a/ \(\frac{14}{15}+\frac{3}{11}+\frac{1}{15}+\frac{3}{11}+\frac{10}{22}=\left(\frac{14}{15}+\frac{1}{15}\right)+\left(\frac{3}{11}+\frac{3}{11}+\frac{2x5}{2x11}\right)=\)
\(=\frac{15}{15}+\frac{11}{11}=1+1=2\)
b/ 9,25+9,25x8+9,25=9,25(1+8+1)=9,25x10=92,5
a. $\dfrac{14}{15}+\dfrac{2}{11}+\dfrac{1}{15}+\dfrac{4}{11}+\dfrac{10}{22}$
$=(\dfrac{14}{15}+dfrac{1}{15})+(\dfrac{2}{11}+\dfrac{4}{11}+\dfrac{10}{22})$
$=1+1=2$
b. $74\times43-43+27\times43$
$=(74-1+27)\times43$
$=100\times43=4300$
\(a)\dfrac{14}{15}+\dfrac{2}{11}+\dfrac{1}{15}+\dfrac{4}{11}+\dfrac{10}{22}\)
\(=\left(\dfrac{14}{15}+\dfrac{1}{15}\right)+\dfrac{2}{11}+\dfrac{4}{11}+\dfrac{5}{11}\)
\(=1+1=2\)
\(b)74\times43-43+27\times43\)
\(=43\times\left(74-1+27\right)\)
\(=43\times100=4300\)
\(=\frac{10}{11}-\frac{3}{7}:\frac{7}{15}:\frac{15}{14}\)
\(=\frac{10}{11}-\frac{45}{49}:\frac{15}{14}\)
\(=\frac{10}{11}-\frac{6}{7}=\frac{70}{77}-\frac{66}{77}=\frac{4}{77}\)