Question

[Bùi Sỹ Bình]

There are 5 teams participating in the math team. The total score is 144 points 5 team and it's interesting that the 5 teams have achieved one of three prizes : Best ( 30 points ) ; second ( 29 points ) ; Three ( 28 points ) . Prove the team than the team won three first prize right one team .

Answer 1

[Bùi Sỹ Bình]

Solution: We find the average of a team and a team prize was the third prize of a team score second. If the team won the first prize by winning three of the total points of the 5 teams are: 29 x 5 = 145 (point)> 144 points, not fulfilled. If the team more than the team's top prize, the third prize total 5 points greater than 145 team, also unsatisfactory. Thus the team must be less than the first prize team third prize. Then we put a team prize and a third team as a pair, the pair will have a total score of the two teams the second prize. Excess number third team (not rated pair with a team prize) is the point where total of 5 points less than 145. So the team of the three first prize more than the team how much they total of 5 145 teams will be smaller than they were. Because the total score of both teams was 144 points 5 team should score more than the third place team prize is 145-144 = 1.

Answer 2

[Trang Sún]

Có 5 đội tham gia trong đội toán . Tổng số điểm là 144 điểm 5 đội bóng và thật thú vị khi 5 đội đã đạt được một trong ba giải thưởng : Best ( 30 điểm ) ; thứ hai ( 29 điểm ) ; Ba ( 28 điểm ) . Chứng minh các nhóm hơn đội giành được ba giải thưởng đầu tiên bên phải một đội bóng.