18 x 11
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\(18+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-36\right]\)
\(\Leftrightarrow\dfrac{198}{11}+\dfrac{1}{11}\times\left(x-18\right)=36+\dfrac{1}{11}\times\left[\dfrac{10}{11}\times\left(x-18\right)-\dfrac{396}{11}\right]\)
\(\Leftrightarrow\dfrac{198+x-18}{11}=36+\dfrac{1}{11}\times\dfrac{10x-180-396}{11}\)
\(\Leftrightarrow\dfrac{180+x}{11}=36+\dfrac{10x-576}{121}\)
\(\Leftrightarrow\dfrac{1980+11x}{121}=\dfrac{4356}{121}+\dfrac{10x-576}{121}\)
\(\Leftrightarrow1980+11x=4356+10x-576\)
\(\Leftrightarrow11x-10x=4356-1980-576\)
\(\Leftrightarrow x=1800\)
Đặt A=-11x107+11.18-11.11
Ta có A=-11x107+11.18-11.11
:= 11.(-107)+11.18-11.11
:=11.[ (-107)+18-11]
=11.(-100)
=-1100
Vậy A= -1100
-11x107+11x18-11x11
=11x(18-11)-11x107
=11x7-11x107
=11x(7-107)
=11x(-100)
=(-1100)
Chúc bạn học giỏi
\(\left(x+7\right)-11=-11+18\\ \Rightarrow x+7=-11+18+11\\ \Rightarrow x+7=18\\ \Rightarrow x=18-7\\ \Rightarrow x=11\)
=9/4x2/3+16/9x4/3
=18/12+64/36
=54/36+64/36=118/36=59/18
\(\Leftrightarrow\left(11+\dfrac{7}{18}-9-\dfrac{13}{18}\right):x=\dfrac{5}{3}+\dfrac{35}{33}\cdot\dfrac{11}{7}=\dfrac{10}{3}\)
\(\Leftrightarrow x=\dfrac{5}{3}:\dfrac{10}{3}=\dfrac{1}{2}\)
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{5\times4\times13}{13\times5\times3}=\dfrac{4}{3}\\ b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\dfrac{3}{7}\times\dfrac{7}{5}+\dfrac{5}{2}\times\dfrac{7}{5}=\dfrac{3}{5}+\dfrac{7}{2}=\dfrac{6}{10}+\dfrac{35}{10}=\dfrac{41}{10}\\ c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
\(\frac{11}{13}-\left(\frac{5^2}{4^2}-x\right)=-\frac{17}{6}\)
\(\frac{11}{13}-\left(\frac{25}{16}-x\right)=-\frac{17}{6}\)
\(\frac{25}{16}-x=\frac{11}{13}-\left(\frac{-17}{6}\right)\)
\(x=\frac{25}{16}-\frac{287}{87}\)
\(x=\frac{-2417}{1592}\)
=198
xì
198 nha bạn