Tìm x
a} (3/4 + x ) . 1/2 = 4/5
b 420 : [75 - (x - 10 )]= 21
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a: x=2/5*15=6
b: =>x-7=15
=>x=22
c: =>3/4:x+1/2*4=4
=>3/4:x=4-2=2
=>x=3/8
a) [ 25 - ( x + 1,85 ) ] : 3 = 7
[ 25 - ( x + 1,85) ] = 7x3
[ 25 - ( x + 1,85 ) ] = 21
x + 1,85= 25-21
x + 1,85= 4
x= 4-1,85
x= 2,15
a) [25 - (x + 1,85)] : 3 = 7
=> 25 - (x + 1,85) = 3 x 7
=> 25 - (x + 1,85) = 21
=> x + 1,85 = 25 - 21
=> x + 1,85 = 4
=> x = 4 - 1,85
=> x = 2,15
b) 420 : [75 - (x - 10)] = 21
=> 75 - (x - 10) = 420 : 21
=> 75 - (x - 10) = 20
=> x - 10 = 75 - 20
=> x - 10 = 55
=> x = 55 + 10
=> x = 65
420:[75-(x-10)]=21
=> 75 - ( x-10) = 420 : 21 = 20
=> x -10 = 75 -20 = 55
=> x = 55 + 10 = 65
420 : [75 - (x - 10)] = 21
75 - (x - 10) = 420 : 21
75 - (x - 10) = 20
x - 10 = 75 - 20
x - 10 = 55
x = 55 + 10
x = 65
Vậy x = 65
420 : [ 75 - ( x - 10) ] = 21
75 - ( x - 10 ) = 420 : 21
75 - ( x - 10 ) = 20
x - 10 = 75 - 20
x -10 = 55
x = 55 + 10
x = 65
a: \(\left(x-4\right)^2-\left(x-3\right)\left(x+3\right)=5\)
\(\Leftrightarrow x^2-8x+16-x^2+9=5\)
\(\Leftrightarrow-8x=-20\)
hay \(x=\dfrac{5}{2}\)
A) \(x-\dfrac{2}{3}=\dfrac{4}{5}\\ x=\dfrac{4}{5}+\dfrac{2}{3}\)
\(x=\dfrac{22}{15}\)
b)\(\dfrac{7}{9}-x=\dfrac{1}{3}\\ x=\dfrac{7}{9}-\dfrac{1}{3}\\ x=\dfrac{4}{9}\)
C)\(x:\dfrac{2}{3}=\dfrac{9}{8}\\ x=\dfrac{9}{8}x\dfrac{2}{3}\\ x=\dfrac{3}{4}\)
a, \(\dfrac{4x}{7}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{3+10}{15}=\dfrac{13}{15}\Rightarrow60x=91\Leftrightarrow x=\dfrac{91}{60}\)
b, \(\dfrac{5}{7}:x=\dfrac{1}{6}+\dfrac{4}{5}=\dfrac{5+24}{30}=\dfrac{29}{30}\Leftrightarrow x=\dfrac{5}{7}:\dfrac{29}{30}=\dfrac{150}{203}\)
Bài 3:
a: Ta có: 60-3(x-2)=51
\(\Leftrightarrow x-2=3\)
hay x=5
b: Ta có: \(4x-20=25:2^2\)
\(\Leftrightarrow4x=\dfrac{25}{4}+20=\dfrac{105}{4}\)
hay \(x=\dfrac{105}{16}\)
c: Ta có: \(8\cdot6+288:\left(x-3\right)^2=50\)
\(\Leftrightarrow288:\left(x-3\right)^2=50-48=2\)
\(\Leftrightarrow\left(x-3\right)^2=144\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=12\\x-3=-12\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=15\\x=-9\end{matrix}\right.\)
a: \(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{5}\\x-\dfrac{3}{4}=-\dfrac{1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{20}\\x=\dfrac{11}{20}\end{matrix}\right.\)
\(a,\left|x-\dfrac{3}{4}\right|=\dfrac{1}{5}\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{4}=\dfrac{1}{5}\\x-\dfrac{3}{4}=\dfrac{-1}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{19}{20}\\x=\dfrac{11}{20}\end{matrix}\right.\)
\(b,\dfrac{-1}{3}+\left|x\right|=0,5\)
\(\Leftrightarrow\left|x\right|=\dfrac{5}{6}\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{5}{6}\\x=\dfrac{-5}{6}\end{matrix}\right.\)
(3/4+x).1/2=4/5
3/4+x=4/5:1/2
3/4+x=8/5
x=8/5-3/4
x=17/20
b)420:[75-(x-10)]=21
75-(x-10)=420:21
75-(X-10)=20
X-10=75-20
X-10=55
X=55+10
X=65
K ĐÓ NHÉ
a) 3/4 + x = 4/5 : 1/2 = 4/5 x 2/1
3/4 + x = 6/5
x = 6/5 - 3/4 = 24/20 - 15/20
x = 9/20
b) tương tự nhưng có điều làm ngoài rồi mới đến ngoặc
Điểm âm của mik chỉ còn 118 nữa thôi, các bn giúp mik nha
ai giúp mik, mik sẽ giúp lại
cảm ơn trc~~~