\(\dfrac{1996.1995-996}{1000+1996.1994}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
1996*1995-1996*1994=1996
(1996*1995-996)-(1996*1994)=1996-996=1000
(1996*1995-996)-(1996*1994+1000)=1996-996-1000=0
=>(1996*1995-996)/(1996*1994+1000)=1( vì tử số bằng mẫu số)
\(\frac{1996.1995-996}{1996.1994+1000}=\frac{\left(1000+996\right).1995-996}{\left(1000+996\right).1994+1000}\)
\(=\frac{1000.1995+996.1995-996}{996.1994+1000.1994+1000}=\frac{1000.1995+996\left(1995-1\right)}{996.1994+1000\left(1994+1\right)}\)
\(=\frac{1000.1995+996.1994}{996.1994+1000.1995}\)=1
\(\frac{1995.1993-18}{1975.1993.1994}\)\(=\frac{1995-18}{1975.1994}\)
\(=\frac{1977}{1975.1994}\)
\(=\frac{1975+2}{1975.1994}\)
\(=\frac{2}{1994}=\frac{1}{997}\)
\(\frac{1996.1995-996}{1000+1996.1994}\)\(=\frac{1995-996}{1994+1000}\)
\(=\frac{999}{1994+1000}\)
\(=\frac{999}{1994+999+1}\)
\(=\frac{1}{1994+1}=\frac{1}{1995}\)
A= \(\dfrac{1993\left(1994+1\right)}{1995\left(1992+1\right)}\)=1
B=\(\dfrac{399\left(45+55\right)}{1995\left(1996-1991\right)}\)=\(\dfrac{399.5.100}{399.5.5}\)=100
\(a,\frac{125\cdot81\cdot7}{49\cdot75\cdot27}=\frac{25\cdot5\cdot9\cdot9\cdot7}{7\cdot7\cdot15\cdot5\cdot3\cdot9}=\frac{25\cdot9}{7\cdot15\cdot3}=\frac{5\cdot5\cdot3\cdot3}{7\cdot3\cdot5\cdot3}=\frac{5}{7}\)
\(b,\frac{48\cdot25-48\cdot11-48}{16\cdot23-16\cdot10}=\frac{1200-528-48}{368-160}=\frac{624}{208}=3\)
\(c,\frac{15\cdot\left[4\cdot17+17\cdot5\right]}{18\cdot25\cdot34}=\frac{15\cdot\left[17\cdot\left(4+5\right)\right]}{15300}=\frac{15\cdot153}{15300}\)
\(=\frac{2295}{15300}=\frac{3}{20}\)
\(d,\frac{1996\cdot1995-996}{1000+1996\cdot1994}=\frac{3982020-996}{1000+3980024}=\frac{3981024}{3981024}=1\)
\(15+\left(1000-998\right)+\left(998-996\right)+\left(996-994\right)+...+\left(102-100\right)+\left(100-98\right)=15+2+2+...+2=15+226\times2=467\)
15+(1000-998)+(998-996)+(996-994)+....+(102-100)+(100-98)
= 15+1000-998+998-996+996-994+....+102-100+100-98
= 15 + 1000 - 98 = 917
y = \(\frac{998}{1000}+\frac{997}{1000}+\frac{996}{1000}+......+\frac{1}{1000}\)
<=>998+997+996+....+1(*)
Số các số hạng là:(998-1)+1=998
tổng của 2 số đầu dãy và cuối dãy là:998+1=999
(*)=999.998:2=997002;2=498501
=>y=\(\frac{498501}{1000}\)
1996 * 1995 - (996 + 1000 + 1996*1996)
= 1996*1995 - (1996 x (1 + 1996))
= 1996*(1995 - 1996 - 1)
= 1996* -2
=-3992
1996 * 1995 - (996 + 1000 + 1996*1996)
= 1996*1995 - (1996 x (1 + 1996))
= 1996*(1995 - 1996 - 1)
= 1996* -2
=-3992
\(\dfrac{1996.1995-996}{1000+1996.1994}=\dfrac{1996\left(1994+1\right)-996}{1000+1996.1994}=\dfrac{1996.1994+1996-996}{1000+1996.1994}\)
\(=\dfrac{1000+1996.1994}{1000+1996.1994}=1\)