\(\frac{43}{20}+\frac{17}{65}:\left(\frac{5}{8}+\frac{7}{30}\right)\)
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\(\frac{43}{20}+\frac{17}{6}:\left[\frac{5}{8}+\frac{7}{30}\right]\)
= \(\frac{43}{20}+\frac{17}{6}:\frac{103}{120}\)
= \(\frac{43}{20}+\frac{340}{103}\)
=\(\frac{11229}{2060}\).
\(\frac{43}{20}+\frac{17}{6}:\left[\frac{5}{8}+\frac{7}{30}\right]\)
\(=\frac{43}{20}+\frac{17}{6}:\left[\frac{103}{120}\right]\)
\(=\frac{43}{20}+\frac{340}{103}=\frac{11229}{2060}\)
\(M=\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{1}{17}+\frac{1}{7}-\frac{-3}{35}\right).\frac{-4}{3}}\)
\(M=\frac{\left(\frac{1}{30}-\frac{7}{20}\right).\frac{5}{19}}{\left(\frac{24}{119}+\frac{3}{35}\right).\frac{-4}{3}}\)
\(M=\frac{\frac{-19}{60}.\frac{5}{19}}{\frac{171}{595}.\frac{-4}{3}}\)
\(M=\frac{-1}{12}:\frac{-228}{595}\)
\(M=\frac{595}{2736}\)
Ta có:
\(M=\frac{\left(\frac{3}{10}-\frac{4}{15}-\frac{7}{20}\right)\times\frac{5}{19}}{\left(\frac{1}{17}+\frac{1}{7}-\frac{-3}{35}\right)\times\frac{-4}{3}}\)
\(M=\frac{\left(\frac{1}{30}-\frac{7}{20}\right)\times\frac{5}{19}}{\left(\frac{24}{119}+\frac{3}{35}\right)\times\frac{-4}{3}}\)
\(M=\frac{\frac{-19}{60}\times\frac{5}{19}}{\frac{171}{595}\times\frac{-4}{3}}\)
\(M=\frac{-1}{12}\div\frac{-228}{595}\)
\(M=\frac{595}{2736}\)
Vậy \(M=\frac{595}{2736}\)
Tìm x, biết:
3(x+2)(x+5) +5(x+5)(x+10) +7(x+10)(x+17) =x(x+2)(x+17) (x∉−2;−5;−10;−17)
2(x−1)(x−3) +5(x−3)(x−8) +12(x−8)(x−20) −1x−20 =−34 (x∉1;3;8;20)
x+110 +2+111 x+112 =x+113 +x+114
x−1030 +x−1443 +x−595 +x−1488 =0
\(=\frac{43}{20}+\frac{17}{65}:\frac{103}{120}\)
\(=\frac{43}{20}+\frac{408}{1339}\)
\(=2,454705004\)
tíc mình nha
\(\frac{43}{20}+\frac{17}{65}:\left(\frac{5}{8}+\frac{7}{30}\right)\)
\(=\frac{43}{20}+\frac{17}{65}:\frac{103}{120}\)
\(=\frac{43}{20}+\frac{408}{1339}\)
\(=2,4547........\)