Tính giá trị biểu thức: 989 - 201 - (100+2 x 5)
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9900 : 36 - 15 x 11
= 275 - 165
= 110
9700 : 100 + 36 x 12
= 97 + 432
= 529
( 15792 : 336 ) x 5 + 27 x 11
= 47 x 5 + 297
= 235 + 297
= 532
( 160 x 5 - 25 x 4 ) : 4
= ( 800 - 100 ) : 4
= 700 : 4
= 175
1036 + 64 x 52 - 1827
= 1036 + 3328 - 1827
= 4364 - 1827
= 2537
215 . 869 + 215 . 14
= 215 . ( 869 + 14 )
= 215 . 883
= 189945
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1: A=4x^2+12x+9-4x^2+4x-1-6x=10x+8
Khi x=201 thì A=10*201+8=2018
2: B=4x^2+20x+25-4x^2+12=20x+37
Khi x=1/20 thì B=1+37=38
1, \(A=\left(2x+3\right)^2-\left(2x-1\right)^2-6x\)
\(A=\left[\left(2x+3\right)+\left(2x-1\right)\right]\left[\left(2x+3\right)-\left(2x-1\right)\right]-6x\)
\(A=\left(2x+3+2x-1\right)\left(2x+3-2x+1\right)-6x\)
\(A=4\left(4x+2\right)-6x\)
\(A=16x+8-6x\)
\(A=10x+8\)
Thay \(x=201\) vào A ta có:
\(A=10\cdot201+8=2010+8=2018\)
Vậy: ....
2, \(B=\left(2x+5\right)^2-4\left(x+3\right)\left(x-3\right)\)
\(B=\left(2x+5\right)^2-4\left(x^2-9\right)\)
\(B=4x^2+20x+25-4x^2+36\)
\(B=20x+61\)
Thay \(x=\dfrac{1}{20}\) vào B ta có:
\(B=20\cdot\dfrac{1}{20}+61=1+61=62\)
Vậy: ...
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a) \(P=x\left(x-y\right)+y\left(x-y\right)=\left(x-y\right)\left(x+y\right)=x^2-y^2=5^2-4^2=9\)
b) \(Q=x\left(x^2-y\right)-x^2\left(x+y\right)+y\left(x^2-x\right)=x^3-xy-x^3-x^2y+x^2y-xy=0\)
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A) \(483+17442:57-175\)
\(=483+306-175\)
\(=614\)
B) \(201\times36:54+1087\)
\(=134+1087\)
\(=1221\)
C) \(994-23374:58+576\)
\(=994-403+576\)
\(=1167\)
`@` `\text {Ans}`
`\downarrow`
`483 + 17442 \div 57 - 175`
`= 483 + 306 - 175`
`= 789 - 175`
`= 614`
`B)`
`201 \times 36 \div 54 + 1087`
`= 7236 \div 54 + 1087`
`= 134 + 1087`
`= 1221`
`C)`
`994 - 23374 \div 58 + 576`
`= 994 - 403 + 576`
`= (994+576) - 403`
`= 1570 - 403`
`=`1167`
989 - 201 - (100 + 2 x 5)
= 989 - 201 -(100 + 10)
= 989 - 201 - 110
= 788 - 110
= 678
989 - 201 - (100+2 x 5) = 989 - 201 - 110 = 678