1000 + x = 1/10(18000 + 9x)
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Bài 1:
a) x.x.y.y.x.y.x = \(x^4.y^3\)
b) 1000.10.10= 1000. \(10^2\)
c) \(3^{15}:3^5=3^{15-5}=3^{10}\)
d) \(9^8:3=3^{16}:3=3^{15}\)
e) \(125:5^3=\dfrac{125}{5^3}=\dfrac{5^3}{5^3}=1\)
B2:
{[(9x+3x-128) x 3] x 10} + 1000 =760
{[(9x+3x-128) x 3] x 10} =760 - 1000
{[(9x+3x-128) x 3] x 10} =-240
{[(9x+3x-128) x 3] x 10} =-240
{[x(9+3)-128] x 3} =-240 : 10
{[x(9+3)-128] x 3} =-24
{[12x-128] x 3} =-24
[12x-128] =-24 : 3
[12x-128] =-8
12x =-8+128
12x =120
x =120:12
x =10
{[(9x+3x-128) x 3] x 10} + 1000 =760
[(x(9+3)-128)x3]x10=760-1000
[(x.12-128)x3]x10=-240
(x.12-128)x3=-240:10
(x.12-128)x3=-24
(x.12-128)=-24:3
x.12-128=-8
x.12=-8+128
x.12=120
x=120:12
x=10
vậy x=10
1.
x.x.y.y.x.y.x=(x.x.x.x) (y.y.y)=x4.y3=(x.y)4.3=xy12
1000.10.10=103.10.10=103+1+1=105
315:35=315–5=310
98:3=(32)8:3=316:3=316–1=315
125:53=53:53=1
1000= 500×2 700= 350×2 90000=30000×3 210000= 70000× 3 2400= 600×4 16000=800×2 18000=9000×2
Ta có;
x+2x+3x+4x+...+9x=1000-100
=>x+2x+3x+4x+...+9x=900
=>(1+2+3+4+....+9)x=900
=>[(1+9).9:2]x=900
=>45x=900
x=900:45=20
cho tớ đúng nha
Ta có;
x+2x+3x+4x+...+9x=1000-100
=>x+2x+3x+4x+...+9x=900
=>(1+2+3+4+....+9)x=900
=>45x=900
x=900:45=20
x=8 nên x+1=9
\(F=x^{13}-9x^{12}+9x^{11}-9x^{10}+...-9x^2+9x-2\)
\(=x^{13}-x^{12}\left(x+1\right)+x^{11}\left(x+1\right)-x^{10}\left(x+1\right)+...-x^2\left(x+1\right)+x\left(x+1\right)-2\)
\(=x^{13}-x^{13}-x^{12}+x^{12}+...-x^3-x^2+x^2+x-2\)
=x-2
=8-2
=6
f: Ta có: \(x\left(2x-9\right)-4x+18=0\)
\(\Leftrightarrow\left(2x-9\right)\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{2}\\x=2\end{matrix}\right.\)
g: Ta có: \(4x\left(x-1000\right)-x+1000=0\)
\(\Leftrightarrow\left(x-1000\right)\left(4x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=1000\\x=\dfrac{1}{4}\end{matrix}\right.\)
f. x(2x - 9) - 4x + 18 = 0
<=> x(2x - 9) - 2(2x - 9) = 0
<=> (x - 2)(2x - 9) = 0
<=> \(\left[{}\begin{matrix}x-2=0\\2x-9=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=2\\x=\dfrac{9}{2}\end{matrix}\right.\)
g. 4x(x - 1000) - x + 1000 = 0
<=> 4x(x - 1000) - (x - 1000) = 0
<=> (4x - 1)(x - 1000) = 0
<=> \(\left[{}\begin{matrix}4x-1=0\\x-1000=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=1000\end{matrix}\right.\)
h. 2x(x - 4) - 6x2(-x + 4) = 0
<=> 2x(x - 4) + 6x2(x - 4) = 0
<=> (2x + 6x2)(x - 4) = 0
<=> 2x(1 + 3x)(x - 4) = 0
<=> \(\left[{}\begin{matrix}2x=0\\1+3x=0\\x-4=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=0\\x=\dfrac{-1}{3}\\x=4\end{matrix}\right.\)
i. 2x(x - 3) + x2 - 9 = 0
<=> 2x(x - 3) + (x - 3)(x + 3) = 0
<=> (2x + x + 3)(x - 3) = 0
<=> (3x + 3)(x + 3) = 0
<=> \(\left[{}\begin{matrix}3x+3=0\\x+3=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=-1\\x=-3\end{matrix}\right.\)
j. 9x - 6x2 + x3 = 0
<=> x(9 - 6x + x2) = 0
<=> x(3 - x)2 = 0
<=> \(\left[{}\begin{matrix}x=0\\3-x=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)
a ) 18 x 10 = 180
18 x 100 = 1800
18 x 1000 = 18000
82 x 100 = 8200
75 x 1000 = 75000
19 x 10 = 190
256 x 1000 = 256000
302 x 10 = 3020
400 x 100 = 40000
b ) 9000 : 10 = 900
9000 : 100 = 90
9000 : 1000 = 9
6800 : 100 = 68
420 : 10 = 42
2000 : 1000 = 2
20020 : 10 = 2002
200200 : 100 = 2002
2002000 : 1000 = 2002
a)18 x 10 = 180
18 x 100 = 1 800
18 x 1000 = 18 000
82 x 100 = 8 200
75 x 1000 = 75 000
19 x 10 = 190
256 x 1000 = 256 000
302 x 10 = 3 020
400 x 100 = 40 000
b)9000 : 10 = 900
9000 : 100 = 90
9000 : 1000 = 9
6800 : 100 = 68
420 : 10 = 42
2000 : 1000 = 2
20 020 : 10 = 2 002
200 200 : 100 = 2 002
2 002 000 : 1000 = 2 002
=> 1000 + x = 1800 + 9/10x
=> 1/10x = 800
=> x = 8000
bạn làm đúng đó !