Tìm X biết X x 14 - X : 1/9 + 1/9 = 3/11
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a,x.(3\4+2\5)=1
x.20\23=1
x=1:20\23
x=20\23
b,x-9\11=0 hoặc x-25\31=0
x=9\11 x=25\31
c,x-3\7.9\14=7\3
x-2\3=7\3
x=7\3+2\3
x=9\3
x=3
(x + 3)(x2 - 3x + 9) - x(x - 1)(x + 1) = 14
<=> x3 + 27 - x(x2 - 1) = 14
<=> x3 + 27 - x3 + x = 14
<=> x3 - x3 + x = 14 - 27
<=> x = -13
\(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-1\right)\left(x+1\right)=14\)
\(\Leftrightarrow x^3+27-x^3+x=14\)
hay x=-13
\(1.x-\dfrac{2}{3}\times\left(x+9\right)=1\)
\(x-\dfrac{2}{3}\times x-6=1\)
\(x\times\left(1-\dfrac{2}{3}\right)=7\)
\(x\times\dfrac{1}{3}=7\)
\(x=21\)
\(2.x-\dfrac{11}{15}=\dfrac{3+x}{5}\)
\(\dfrac{15x}{15}-\dfrac{11}{15}=\dfrac{9+3x}{15}\)
\(15x-11=9+3x\)
\(12x=20\)
\(x=\dfrac{5}{3}\)
a: \(\dfrac{x}{0.9}=\dfrac{5}{6}\)
\(\Leftrightarrow x=\dfrac{3}{4}\)
b: \(\dfrac{-6}{x}=\dfrac{9}{-15}\)
\(\Leftrightarrow x=10\)
c: \(\dfrac{\dfrac{14}{15}}{\dfrac{9}{10}}=\dfrac{x}{\dfrac{3}{7}}\)
\(\Leftrightarrow x=\dfrac{3}{7}\cdot\dfrac{14}{15}:\dfrac{9}{10}=\dfrac{2}{5}\cdot\dfrac{10}{9}=\dfrac{20}{45}=\dfrac{4}{9}\)
Để mình viết đề lại cho nhé:
\(x\times14-x:\frac{1}{9}+\frac{1}{9}=\frac{3}{11}\)
\(x\times14-x\times9+\frac{1}{9}=\frac{3}{11}\)
\(x\times\left(14-9\right)=\frac{3}{11}-\frac{1}{9}\)
\(x\times5=\frac{27}{99}-\frac{11}{99}\)
\(x\times5=\frac{16}{99}\)
\(x=\frac{16}{99}:5\)
\(x=\frac{16}{495}\)
x * 14 - x : 1/9 + 1/9 = 3/11
x * 14 - x * 9 + 1/9 = 3/11
x * (14 - 9) + 1/9 = 3/11
x * 5 + 1/9 = 3/11
x * 5 = 3/11 - 1/9
x * 5 = 16/99
x = 16/99 : 5
x = 16/495