Tìm số tự nhiên X biết: \(1\frac{1}{5}\) x \(1\frac{1}{6}\) x \(1\frac{1}{7}\) x ... x \(1\frac{1}{2014}\) = X
Trả lời: X = ...
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\(1\frac{1}{5}\)X \(1\frac{1}{6}\) X \(1\frac{1}{7}\) X \(...\)X \(1\frac{1}{2014}\) = x
x = \(\frac{6}{5}\) X \(\frac{7}{6}\) X \(\frac{8}{7}\) X \(...\)X \(\frac{2015}{2014}\)
x = \(\frac{6\cdot7\cdot8\cdot...\cdot2015}{5\cdot6\cdot7\cdot...2014}\)
x = \(\frac{2015}{5}\)
x = 403
6/5 × 7/6 × 8/7 × ... × 2015/2014 = x
2015/5 = x
x = 403
Vậy x = 403
Ủng hộ mk nha ♡_♥☆_★^_-
\(1\frac{1}{5}\cdot1\frac{1}{6}\cdot...\cdot1\frac{1}{2014}=x\)
\(\frac{6}{5}\cdot\frac{7}{6}\cdot...\cdot\frac{2015}{2014}=x\)
\(\frac{6\cdot7\cdot...\cdot2015}{5\cdot6\cdot...\cdot2014}=x\)
\(\frac{2015}{5}=x\)
\(2015:5=x\)
\(403=x\)
Vậy : \(x=403\)
\(\frac{6}{5}x\frac{7}{6}x\frac{8}{7}x...x\frac{2015}{2014}=\frac{2015}{5}=403=>X=403\)
X=\(\frac{6}{5}.\frac{7}{6}....\frac{2015}{2014}\)
=\(\frac{2015}{5}\)
=403
bạn cứ nhân ra là xong
\(X=\frac{6}{5}x\frac{7}{6}x\frac{8}{7}x....x\frac{2014}{2013}=\frac{2014}{5}\)
\(=\frac{6}{5}.\frac{7}{6}.\frac{8}{7}............\frac{2015}{2014}=\frac{2015}{5}=403\)
=> \(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2014}{2013}.\frac{2015}{2014}=x\)
=> \(\frac{6.7.8.9...2014.2015}{5.6.7.8...2013.2014}=x\)
=> \(x=\frac{2015}{5}=403\)
\(1\frac{1}{5}\times1\frac{1}{6}\times.......\times1\frac{1}{2014}=x\)
\(\frac{6}{5}.\frac{7}{6}.........\frac{2015}{2014}=x\)
\(\frac{2015}{5}=x\)
\(x=403\)
\(1\frac{1}{5}.1\frac{1}{6}.1\frac{1}{7}...1\frac{1}{2014}=x\)
\(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2015}{2014}=x\)
\(\frac{2015}{5}=x\)
\(x=403\)
Vậy x = 403
Ủng hộ mk nha ^_^