\(\frac{8.27-64}{8.35+24}\)
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a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5^{300-289}=5^{11}\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}}{3^{17}}=\frac{1}{3}\)
a) \(\frac{125^{100}.2^{160}}{5^{289}.4^{80}}=\frac{\left(5^3\right)^{100}.2^{160}}{5^{289}.\left(2^2\right)^{80}}=\frac{5^{300}.2^{160}}{5^{289}.2^{160}}=5\)
b) \(\frac{9^8.8^8}{3^8.27^3.2^{24}}=\frac{\left(3^2\right)^8.\left(2^3\right)^8}{3^8.\left(3^3\right)^3.2^{24}}=\frac{3^{16}.2^{24}}{3^8.3^9.2^{24}}=\frac{3^{16}.2^{24}}{3^{17}.2^{24}}=\frac{1}{3}\)
62.87+35.14+4.13+8.35+4.35+5.65
=35.(4+5+14)+62.87+5.65+4.13
=35.23+62.87+5.65+4.13
=6576
\(\frac{2^{10}.55+2^{10}.26}{2^8.27}=\frac{2^{10}.\left(55+26\right)}{2^8.27}=\frac{2^2.81}{27}=\frac{2^2.3^3}{3^2}=2^2.3=4.3=12\)
\(\frac{2^{10}.55+2^{10}.26}{2^8.27}\)
\(=\frac{2^{10}.\left(55+26\right)}{2^8.3^3}\)
\(=\frac{2^{10}.81}{2^8.3^3}\)
\(=\frac{2^{10}.3^4}{2^8.3^3}\)
\(=\frac{2^8.2^2.3^3.3}{2^8.3^3}\)
\(=2^2.3=4.3=12\)
\(\frac{32^3.6.9^4}{4^8.27^3}\)
=\(\frac{\left(2^5\right)^3.2.3.\left(3^2\right)^4}{\left(2^2\right)^8.\left(3^3\right)^3}\)
=\(\frac{2^{15}.2.3.3^8}{2^{16}.3^9}\)
=\(\frac{2^{16}.3^9}{2^{16}.3^9}\)
= 1
\(\frac{40}{64}=\frac{...}{24}\)
Gọi số cần tìm là x
\(\Rightarrow40\times24=64.x\)
\(\Rightarrow960=64.x\)
\(\Rightarrow x=960:64\)
\(\Rightarrow x=15\)
~ Hok tốt ~
Ta có :
40/64 = 40 : 8 / 64 : 8 = 5/8
=> 5/8 = .../24
Mà 5/8 = 5 . 3 / 8 . 3 = 15/24
=> 15/24 = .../24
Vậy số cần tìm là 15
#Louis
a) Ta có: \(\frac{\frac{4}{17}-\frac{4}{177}-\frac{4}{1779}}{\frac{5}{17}-\frac{5}{177}-\frac{5}{1779}}=\frac{4.\left(\frac{1}{7}-\frac{1}{177}-\frac{1}{1779}\right)}{5.\left(\frac{1}{7}-\frac{1}{177}-\frac{1}{1779}\right)}=\frac{4}{5}\)
b) \(\frac{1330}{1331}-\frac{7}{1.8}-\frac{19}{8.27}-.....-\frac{331}{1000.1331}\)
\(=\frac{1330}{1331}-\left(\frac{8-7}{1.8}+\frac{27-8}{8.27}+.....+\frac{1331-1000}{1000.1331}\right)\)
\(=\frac{1330}{1331}-\left(1-\frac{1}{8}+\frac{1}{8}-\frac{1}{27}+....+\frac{1}{1000}-\frac{1}{1331}\right)\)
\(=\frac{1330}{1331}-\left(1-\frac{1}{1331}\right)\)
\(=\frac{1330}{1331}-\frac{1330}{1331}=0\)
Vậy \(\frac{1330}{1331}-\frac{7}{1.8}-\frac{19}{8.27}-....\frac{331}{1000.1331}=0\)
CHÚC BẠN HỌC TỐT
a) \(\frac{\frac{4}{17}-\frac{4}{177}-\frac{4}{1779}}{\frac{5}{17}-\frac{5}{177}-\frac{5}{1779}}\)
\(=\frac{4\left(\frac{1}{17}-\frac{1}{177}-\frac{1}{1779}\right)}{5\left(\frac{1}{17}-\frac{1}{177}-\frac{1}{1779}\right)}\)
\(=\frac{4}{5}\)
mình biết đáp án là : \(\frac{9}{16}\)thôi,còn cách giải thì mình không chắc chắn nên không viết ra
\(\frac{3.2.4.3.5.4.6.5.7.6.8.7.9}{4.3.3.4.4.5.5.6.6.7.7.8.8}\)= \(\frac{9}{16}\)
\(A=\frac{8}{9}.\ \frac{15}{16}.\ \frac{24}{25}.\ \frac{35}{36}.\ \frac{48}{49}.\ \frac{63}{64}\)
\(A=\frac{2.4}{3^2}.\ \frac{3.5}{4^2}.\ \frac{4.6}{5^2}.\ \frac{5.7}{6^2}.\ \frac{6.8}{7^2}.\ \frac{7.9}{8^2}\)
\(A=\frac{2.3.4^2.5^2.6^2.7^2.8.9}{3^2.4^2.5^2.6^2.7^2.8^2}\)
\(A=\frac{2.9}{3.8}\)
\(A=\frac{3}{4}\)