Bỏ dấu ngoặc rồi tính:
-( 251. 3+ 281 )+ 3. 251- (1- 281 )
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\(C=\left(-251\cdot3+251\cdot3\right)+\left(-281+281\right)-1=-1\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3=-6,8\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-753-281+645-1+281\)
\(=-753+654-1=-100\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(\dfrac{-3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}=\dfrac{-3}{5}-\dfrac{2}{5}=-1\)
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)\)
\(=3,1-2,5+2,5-3,1\)
\(=\left(3,1-3,1\right)-\left(2,5-2,5\right)\)
\(=0\)
Vậy \(A=0.\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)\)
\(=5,3-2,8-4-5,3\)
\(=\left(5,3-5,3\right)-\left(2,8+4\right)\)
\(=-\dfrac{34}{5}\)
Vậy \(B=\dfrac{-34}{5}.\)
\(C=-\left(251.3+281\right)+3.215-\left(1-281\right)\)
\(=-251.3-281+3.215-1+281\)
\(=-753-\left(281-281\right)+645\)
\(=-753+645=-108\)
Vậy \(C=-108.\)
\(D=-\left(\dfrac{3}{5}+\dfrac{3}{4}\right)-\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\)
\(=-\dfrac{3}{5}-\dfrac{3}{4}+\dfrac{3}{4}-\dfrac{2}{5}\)
\(=\left(\dfrac{-3}{5}-\dfrac{2}{5}\right)-\left(\dfrac{3}{4}-\dfrac{3}{4}\right)\)
\(=-1\)
Vậy D = -1.
C = - (251.3 + 281) + 3.251 – (1- 281)
= -251.3 -281 + 251.3 -1 + 281
= (-251.3 + 251.3 )+ ( -281 + 281) -1
= 0 + 0 - 1 = -1.
a) -(251 x3 + 281) + 3x 251- (1-281) b) \(-\left(\frac{3}{54}+\frac{3}{4}\right)-\left(\frac{-3}{4}+\frac{2}{5}\right)\)
=-251x3 - 281+3 x 251- 1+ 281 =\(\frac{-1}{18}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}\)
=[(-251 x 3)+ (3 x 251)]+(281-281) -1 = (\(\frac{3}{4}-\frac{3}{4}\))-(\(\frac{2}{5}+\frac{1}{18}\))
=0+ 0-1 =0 -41/ 90
=\(-\frac{41}{90}\)
= -1
Bài làm:
Ta có: \(-\left(251.3+281\right)+3.251-\left(1-281\right)\)
\(=-251.3-281+3.251-1+281\)
\(=\left(-251.3+251.3\right)+\left(281-281\right)-1\)
\(=0-0-1=-1\)
- (251 * 3 + 281) + 3 * 251 - (1 - 281)
= -( 753+281) + 753 - -280
= -1034 + 753 - -280
= -281- -280
= -561
-(251 . 3 + 281) + 3 .251 - (1 - 281 )
= -251 . 3 - 281 + 3 . 251 - 1 + 281
= ( 3 . 251 - 251 . 3 ) + ( 281 - 281 ) -1
= 0 + 0 - 1 = - 1
dễ mà bạn !!!
A= (3,1 - 2,5) - (-2,5 + 3,1)
=3.1-2.5+2.5-3.1
=0
B= (5,3 - 2,8) - (4 + 5,3)
=5.3 - 2.8-4-5.3
= -6.8
C= -(251.3 + 281) + 3.251 - (1-281)
=-251.3-281+3.251-1+281
=-1
D= -(3/5+3/4)−(−3/4+2/5)
= -3/5-3/4+3/4-2/5
= -5/5
=-1
\(A=\left(3,1-2,5\right)-\left(-2,5+3,1\right)=3,1-2,5+2,5-3,1=0\)
\(B=\left(5,3-2,8\right)-\left(4+5,3\right)=5,3-2,8-4-5,3=-6,8\)
\(C=-\left(215\cdot3+281\right)+3\cdot215-\left(1-281\right)=-215\cdot3-281+3\cdot215-1+281=1\)
\(D=-\left(\frac{3}{5}+\frac{3}{4}\right)-\left(-\frac{3}{4}+\frac{2}{5}\right)=-\frac{3}{5}-\frac{3}{4}+\frac{3}{4}-\frac{2}{5}=-1\)
-(3251+415)-(2000+585-251)
= -3251-415-2000-585+251
=(-3251+251)+(415+585)+2000
=-3000 + 1000 + 2000
=0
k cho mk nhoa
=-251.3-281+3.251-1+281
=(-251.3+3.251)+(281-281)-1
=0+0-1
=-1