tinh nhanh
B = 2/5x7 + 3/7x10 + 4/10x14 + 7/14x21 + 9/21x30
B = ?
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B = 2/5x7 + 3/7x10 + 4/10x14 + 7/14x21 + 9/21x30
B = 1/5 - 1/7 + 1/7 - 1/10 + 1/10 - 1/14 + 1/14 - 1/21 + 1/21 - 1/30
B = 1/5 - 1/30
B = 6/30 - 1/30
B = 5/30 = 1/6
soyeon làm sai vì nó là 2/5x7 chứ có phải là 1/5x7 đâu mà lại tách ra như thế?
b1
a) \(\dfrac{1}{5.6}+\dfrac{1}{6.7}+\dfrac{1}{7.8}+\dfrac{1}{8.9}+\dfrac{1}{9.10}\)
\(=\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{5}-\dfrac{1}{10}\)
\(=\dfrac{2}{10}-\dfrac{1}{10}\)
\(=\dfrac{1}{10}\)
b) \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\)
\(=\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{99}-\dfrac{1}{100}\)
\(=\dfrac{1}{1}-\dfrac{1}{100}\)
\(=\dfrac{99}{100}\)
c) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\)
\(=\dfrac{1}{3}-\dfrac{1}{11}\)
\(=\dfrac{8}{33}\)
d) \(\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{99.101}\)
\(=\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\)
\(=\dfrac{1}{3}-\dfrac{1}{101}\)
\(=\dfrac{98}{303}\)
Bài 2 :
Ta có :
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}=\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+\left(\frac{1}{8}-\frac{1}{16}\right)+\left(\frac{1}{16}-\frac{1}{32}\right)\)
\(=1-\frac{1}{32}\)
và \(B=\frac{2003}{2004}=1-\frac{1}{2004}\)
Vì \(\frac{1}{32}>\frac{1}{2004}\) nên A < B
B = 2/5x7 + 3/7x10 + 4/10x14 + 7/14x21 + 9/21x30
B = 1/5 - 1/7 + 1/7 - 1/10 + 1/10 - 1/14 + 1/14 - 1/21 + 1/21 - 1/30
B = 1/5 - 1/30
B = 6/30 - 1/30
B = 5/30 = 1/6