72/90 + 7/28
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a)25/50 + 5/15 = 1/2 + 1/3 = 5/6
b)72/90 + 7/28 = 4/5 + 1/4 =\(1\frac{1}{20}\)
c)32/96 + 8/28 = 1/3 + 2/7 = 13/21
Chúc bạn tết vui vẻ nha!
\(\frac{25}{50}+\frac{5}{15}=\frac{1}{2}+\frac{1}{3}=\frac{3}{6}+\frac{2}{6}=\frac{5}{6}\)
\(\frac{72}{90}+\frac{7}{28}=\frac{8}{10}+\frac{1}{4}=\frac{32}{40}+\frac{10}{40}=\frac{42}{40}=\frac{21}{20}\)
\(\frac{32}{96}+\frac{8}{28}=\frac{1}{3}+\frac{2}{7}=\frac{7}{21}+\frac{6}{21}=\frac{13}{21}\)
a, \(\frac{25}{50}\)= \(\frac{25:25}{50:25}\)= \(\frac{1}{2}\) \(\frac{5}{15}\)= \(\frac{5:5}{15:5}\)= \(\frac{1}{3}\)
\(\frac{1}{2}\)+ \(\frac{1}{3}\)= \(\frac{3}{6}\)+ \(\frac{2}{6}\)= \(\frac{5}{6}\)
b, \(\frac{72}{90}\)= \(\frac{72:18}{90:18}\)= \(\frac{4}{5}\) \(\frac{7}{28}\)= \(\frac{7:7}{28:7}\)= \(\frac{1}{4}\)
\(\frac{4}{5}\)+ \(\frac{1}{4}\) = \(\frac{16}{20}\)+ \(\frac{5}{20}\)= \(\frac{21}{20}\)
c, \(\frac{32}{96}\)= \(\frac{32:32}{96:32}\)= \(\frac{1}{3}\) \(\frac{8}{28}\)= \(\frac{8:4}{28:4}\)= \(\frac{2}{7}\)
\(\frac{1}{3}\)+ \(\frac{2}{7}\) = \(\frac{7}{21}\)+ \(\frac{6}{21}\)= \(\frac{13}{21}\)
Lời giải và hướng dẫn:
a) 25/50 + 5/15 = 1/2 + 1/3 = 3/6 + 2/6 = 5/6.
b) 72/90 + 7/28 = 4/5 + 1/4 = 16/20 + 5/20 = 21/20.
c) 32/96 + 8/28 = 1/3 + 2/7 = 7/21 + 6/21 = 13/21.
A)\(\frac{25}{50}+\frac{5}{15}\)
\(=\frac{1}{2}+\frac{1}{3}\)
\(=\frac{3+2}{6}\)\(=\frac{5}{6}\)
B) \(\frac{72}{90}+\frac{7}{28}\)\(=\frac{4}{5}+\frac{1}{4}\)\(=\frac{16+5}{20}\)\(=\frac{21}{20}\)
C)\(\frac{32}{96}+\frac{8}{28}\)\(=\frac{1}{3}+\frac{2}{7}\)\(=\frac{7+6}{21}\)=\(\frac{13}{21}\)
NĂM MỚI VUI VẺ
\(\dfrac{15}{35}+\dfrac{7}{10}=\dfrac{3}{7}+\dfrac{7}{10}=\dfrac{30}{70}+\dfrac{49}{70}=\dfrac{79}{70}\)
\(\dfrac{27}{72}+\dfrac{11}{24}=\dfrac{3}{8}+\dfrac{11}{24}=\dfrac{9}{24}+\dfrac{11}{24}=\dfrac{20}{24}=\dfrac{5}{6}\)
\(\dfrac{6}{12}+\dfrac{7}{6}=\dfrac{1}{2}+\dfrac{7}{6}=\dfrac{3}{6}+\dfrac{7}{6}=\dfrac{10}{6}=\dfrac{5}{3}\)
\(\frac{28}{35}\times\frac{15}{72}\times1\frac{7}{49}=\frac{4}{5}\times\frac{5}{24}\times\frac{8}{7}=\frac{160}{840}=\frac{4}{21}\)
So sánh à bạn !?
Ta có: \(\frac{2}{35}\cdot\frac{15}{72}\cdot1=\frac{1}{84}\)
Ta lại có: \(\frac{7}{49}=\frac{7:7}{49:7}=\frac{1}{7}\)
Giờ ta đã có \(\frac{1}{84}and\frac{1}{7}\)
Ta có: Trong các phân số, phân số nào có mẫu nhỏ hơn thì phân số đó lớn hơn
Mà ta có: 1/7 có mẫu bé hơn
=> \(\frac{2}{35}\cdot\frac{15}{72}\cdot1< \frac{7}{49}\)
=\(\dfrac{21}{20}\)
\(\dfrac{4}{5}+\dfrac{1}{4}=\dfrac{21}{20}\)