\(\dfrac{6}{8}...\dfrac{9}{5}\)
~so sánh~
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a) \(\dfrac{5}{9}< \dfrac{7}{9}\)
b) \(\dfrac{7}{6}>\dfrac{6}{6}\)
c) \(\dfrac{3}{14}< \dfrac{5}{14}\)
d) \(\dfrac{5}{8}< \dfrac{9}{8}\)
a: \(\dfrac{-7}{6}=\dfrac{-7\cdot3}{6\cdot3}=\dfrac{-21}{18}\)
\(\dfrac{-11}{9}=\dfrac{-11\cdot2}{9\cdot2}=\dfrac{-22}{18}\)
mà -21>-22
nên \(-\dfrac{7}{6}>-\dfrac{11}{9}\)
b: \(\dfrac{5}{-7}=\dfrac{-5}{7}=\dfrac{-5\cdot5}{7\cdot5}=\dfrac{-25}{35}\)
\(\dfrac{-4}{5}=\dfrac{-4\cdot7}{5\cdot7}=\dfrac{-28}{35}\)
mà -25>-28
nên \(\dfrac{5}{-7}>\dfrac{-4}{5}\)
c: \(\dfrac{-8}{7}< -1\)
\(-1< -\dfrac{2}{5}\)
Do đó: \(-\dfrac{8}{7}< -\dfrac{2}{5}\)
d: \(-\dfrac{2}{5}< 0\)
\(0< \dfrac{1}{3}\)
Do đó: \(-\dfrac{2}{5}< \dfrac{1}{3}\)
a: \(\dfrac{5}{24}< \dfrac{15}{24}=\dfrac{5}{8}\)
b: \(\dfrac{6+9}{6\cdot9}=\dfrac{15}{54}\)
4/9=24/54
2/3=36/54
Do đó: \(\dfrac{15}{54}< \dfrac{24}{54}< \dfrac{36}{54}\)
a)\(\dfrac{-8}{9}< \dfrac{-7}{9}\\ \dfrac{6}{7}< \dfrac{11}{10}\)
6/8 < 9/5
vì : \(\dfrac{6}{8}< 1;\dfrac{9}{5}>1\\ \Rightarrow\dfrac{6}{8}< \dfrac{9}{5}\)