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a: 3/5=9/15
7/3=35/15
b: 9/10=36/40
5/4=50/40
c: 2/7=8/28
5/4=35/28
d: 8/9=16/18
11/6=33/18
e: 6/5=48/40
13/8=65/40
g: 4/5=8/10
3/2=15/10
h: 5/12=10/24
7/8=21/24
i: 11/4=33/12
13/6=26/12
Bài 2:
\(a,\dfrac{2\times6\times13}{5\times13\times6}=\dfrac{2}{5}\\ b,\dfrac{8\times11\times13}{11\times13\times16}=\dfrac{8}{16}=\dfrac{8}{8\times2}=\dfrac{1}{2}\\ c,\dfrac{5\times18\times12}{15\times24\times16}=\dfrac{5\times3\times3\times6\times3\times4}{3\times5\times4\times6\times4\times4}=\dfrac{3\times3}{4\times4}=\dfrac{9}{16}\\ d,\dfrac{15\times8\times4}{32\times3\times5}=\dfrac{5\times3\times8\times4}{4\times8\times3\times5}=\dfrac{1}{1}=1\)
Bài 1:
\(a,\dfrac{8}{12}=\dfrac{8:4}{12:4}=\dfrac{2}{3}\\ \dfrac{20}{48}=\dfrac{20:4}{48:4}=\dfrac{5}{12}\\ \dfrac{74}{100}=\dfrac{74:2}{100:2}=\dfrac{37}{50}\\ \dfrac{18}{21}=\dfrac{18:3}{21:3}=\dfrac{6}{7}\\ \dfrac{40}{54}=\dfrac{40:2}{54:2}=\dfrac{20}{27}\\ \dfrac{30}{45}=\dfrac{30:15}{45:3}=\dfrac{2}{3}\\ b,\dfrac{18}{24}=\dfrac{18:6}{24:6}=\dfrac{3}{4}\\ \dfrac{49}{28}=\dfrac{49:7}{28:7}=\dfrac{7}{4}\\ \dfrac{15}{35}=\dfrac{15:5}{35:5}=\dfrac{3}{7}\\ \dfrac{28}{40}=\dfrac{28:4}{40:4}=\dfrac{7}{10}\\ \dfrac{36}{27}=\dfrac{36:9}{27:9}=\dfrac{4}{3}\\ \dfrac{56}{49}=\dfrac{56:7}{49:7}=\dfrac{8}{7}\)
\(c,\dfrac{85}{51}=\dfrac{85:17}{51:17}=\dfrac{5}{3}\\ \dfrac{1515}{2323}=\dfrac{1515:101}{2323:101}=\dfrac{15}{23}\\ \dfrac{39}{26}=\dfrac{39:13}{26:13}=\dfrac{3}{2}\\ \dfrac{323232}{515151}=\dfrac{323232:10101}{515151:10101}=\dfrac{32}{51}\)
\(\dfrac{8\times3\times4}{16\times3}\)
\(=\dfrac{8\times3\times2\times2}{8\times2\times3}\)
b) \(\dfrac{30\times25\times7\times8}{75\times8\times12\times14}\)
1.There is a small pond in front of Lam's house.
2.You can play games in the afternoon but you must do your homework in the evening.
3.Does Lan walk or ride a bike to school?
4.When it is hot,We often go swimming.
5.What is there in front of your house?
6.Where is your father sitting now?
7.My class starts at seven in the morning.
8.I do not often go swimming with my friends.
Sau 1 giờ vòi chảy được:
1/3+1/5+1/6=10/30+6/30+5/30=7/10(bể)
Sau 1 giờ thì bể còn:
1-7/10=3/10(bể không chứa nước)
1: Xét ΔMNP vuông tại M có MH là đường cao
nên MH^2=HN*HP; MN^2=NH*NP; PM^2=PH*PN
=>MH=căn 3,6*6,4=4,8cm; MN=căn 3,6*10=6cm; PM=căn 6,4*10=8cm
2: MK=8/2=4cm
Xét ΔMNK vuông tại M có tan MNK=MK/MN=4/6=2/3
nên \(\widehat{MNK}\simeq33^041'\)
3: ΔMNK vuông tại M có MF là đường cao
nên NF*NK=NM^2
ΔMNP vuông tại M có MH là đường cao
nên NH*NP=NM^2
=>NF*NK=NH*NP
\(\dfrac{2}{3};\dfrac{4}{6}\)
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