X x 1,5 + X + X x 2,5 =25
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tìm x , biết :
a . 1,5 . x + 2,5 = 1
\(1,5.x=-1,5\)
\(x=\dfrac{-1,5}{1,5}\)
\(x=-1\)
b . ( 0,5 . x - 1,3 ) : 0,5 = -1,7
\(0,5.x-1,3=-0,85\)
\(0,5x=-2,15\)
\(x=\dfrac{-2,15}{0,5}\)
\(x=-4,3\)
c . 1,75 .x - 1,5 . x = 0,84
\(x\left(1,75-1,5\right)=0,84\)
\(x.0,25=0,84\)
\(x=3,36\)
d . x + 75% . x + 125% = 1
\(x+\dfrac{75}{100}.x+\dfrac{125}{100}=1\)
\(x+\dfrac{3}{4}.x+\dfrac{5}{4}=1\)
\(x+\dfrac{3}{4}.x=-\dfrac{1}{4}\)
\(x.\left(1+\dfrac{3}{4}\right)=-\dfrac{1}{4}\)
\(x.1,75=-\dfrac{1}{4}\)
\(x=-\dfrac{1}{7}\)
e . x - 25% .x + 75% = 1
\(x-\dfrac{25}{100}.x+\dfrac{75}{100}=1\)
\(x-\dfrac{1}{4}.x+\dfrac{3}{4}=1\)
\(x-\dfrac{1}{4}.x=\dfrac{1}{4}\)
\(x.\left(1-\dfrac{1}{4}\right)=\dfrac{1}{4}\)
\(x.\dfrac{3}{4}=\dfrac{1}{4}\)
\(x=\dfrac{1}{3}\)
f . | x - 1,5 | = 2,37
TH1 : \(x-1,5=2,37\)
\(x=2,37+1,5\)
\(x=3,87\)
TH2 : \(x-1,5=-2,37\)
\(x=-2,37+1,5\)
\(x=-0,87\)
a, \(x+30\%x+1,5x=2,5\\ < =>x+0,3x+1,5x=2,5\\ < =>\left(1+0,3+1,5\right)x=2,5\\ < =>2,5x=2,5\\ =>x=\dfrac{2,5}{2,5}=1\)
b, \(2\left(3x-4\right)-3\left(x+2\right)=3\\ < =>6x-8-3x-6=3\\ < =>6x-3x=3+8+6\\ < =>3x=17\\ =>x=\dfrac{17}{3}\)
c, \(-110+7x-80=25+2x-80\\ < =>-110-80+80-25=2x-7x\\ < =>-135=-5x\\ =>x=\dfrac{-135}{-5}=27\)
a,2,5-x=1,3
x=2,5-1,3
x=1,2
b,x-3,5=7,5
x=7.5+3,5
x=11
c,(x-1,5)-2,5=0
x-1,5=2,5
x=2,5+1,5
x=4
d,1,6-(x-0,2)=0
x-0,2=1,6
x=1,6+0,2
x=1,8
A=(3,7- -x)+2,5
vì 2,5>=0 với mọi x
=> x=-1,2
B= (x+1,5)-4,5
Vì -4,5<=0 với mọi x
=> x=-6
Học Tốt
Th1
x-1,5+2,5-x=0
<=>0x=-1
=> vô lí
Th2
-x+1,5-2,5+x=0
<=>0x=1
=>vô lí
vậy không có x thỏa mãn
\(a,x+3,79=15,12\)\(\Rightarrow x=15,12-3,79\)\(\Rightarrow x=11,33\)
\(b,12,1-x=5,49\)\(\Rightarrow x=12,1-5,49\Rightarrow x=6,61\)
\(c,60,45:x=1,5\)\(\Rightarrow x=60,45:1,5\Rightarrow x=40,3\)
\(d,3,5.x-1,5.x=12,5\)
\(\Rightarrow x\left(3,5-1,5\right)=12,5\)
\(\Rightarrow x.2=12,25\Rightarrow x=12,25:2=6,125\)
\(d,12,5.x-2,5.x-50=2,5.10\)
\(\Rightarrow12,5.x-2,5.x-50=25\)
\(\Rightarrow x\left(12,5-2,5\right)=25+50\)
\(\Rightarrow x.10=75\)
\(\Rightarrow x=75:10=7,5\)
a) x=11,33 b) x=6,61 c)40,3
Mình chỉ biết làm tới đó thôi. xin lỗi nha
a) 8,8 : 2,5 + 7,6 : 2,5 - 6,4 : 2,5
= (8,8 + 7,6 - 6,4) : 2,5
= 10 : 2,5
= 4
\(a.\)
\(8.8:2.5+7.6:2.5-6.4:2.5\)
\(=\left(8.8+7.6-6.4\right):2.5\)
\(=10:2.5\)
\(=4\)
\(b.\)
\(0.25\times1200+125\times1.5\times2-250\times2.6\)
\(=250\times1.2+250\times1.5-250\times2.6\)
\(=250\times\left(1.2+1.5-2.6\right)\)
\(=250\times0.1=25\)
\(c.\)
\(\left(32\times11-3200\times0.1-32\right):\left(81.6\times27.3-17.3\times81.6\right)\)
\(=\left[32\times\left(11-10-1\right)\right]:\left[81.6\times\left(27.3-17.3\right)\right]\)
\(=0\)
\(x.2,5-x.1,5=5\)
\(x.\left(2,5-1,5\right)\)\(=5\)
\(x.1=5\)
\(x=5:1\)
\(x=5\)
\(\left|2.5-x\right|=1.3\)
\(\Rightarrow\begin{cases}2.5-x=1.3\\2.5-x=-1.3\end{cases}\Rightarrow\begin{cases}x=1.2\\x=3.8\end{cases}\)
1,6 - | x - 0,2 | = 0
| x - 0,2 |=16
\(=>\left\{{}\begin{matrix}x-0,2=16\\x-0,2=-16\end{matrix}\right.=>\left\{{}\begin{matrix}x=16,2\\x=-15,8\end{matrix}\right.\)
Vậy x=\(\left\{{}\begin{matrix}16,2\\-15,8\end{matrix}\right.\)
a)\(\left|x-3,5\right|=0,25\)
\(\Leftrightarrow\orbr{\begin{cases}x-3,5=0,25\\x-3,5=-0,25\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3,75\\x=3,25\end{cases}}}\)
b)\(\left|1,5-x\right|=1,75\)
\(\Leftrightarrow\orbr{\begin{cases}1,5-x=1,75\\1,5-x=-1,75\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-0,25\\x=3,25\end{cases}}}\)
c)\(\left|x-1,5\right|=1,5\)
\(\Leftrightarrow\orbr{\begin{cases}x-1,5=1,5\\x-1,5=-1,5\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=0\end{cases}}}\)
=> X x ( 1,5 + 1 + 2,5 ) = 25
=> X x 5 = 25
=> X = 25 : 5
=> X = 5 (tm)
Ai k mk mk k lại !!
X x 1,5 + X + X x 2,5 =25
=X x (1,5+1+2,5)
X x 5=25
X=25:5
X=5