11/30 -9/25 nhân 15/27
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NK
14 tháng 5 2023
\(\dfrac{11}{30}-\dfrac{9}{25}\times\dfrac{15}{27}=\dfrac{11}{30}-\dfrac{9}{25}\times\dfrac{5}{9}=\dfrac{11}{30}-\dfrac{45}{225}\)
\(=\dfrac{11}{30}-\dfrac{1}{5}=\dfrac{11}{30}-\dfrac{6}{30}=\dfrac{5}{30}=\dfrac{1}{6}\)
TH
1
19 tháng 7 2019
\(25\frac{2}{13}-\left(\frac{15}{17}+15\frac{2}{3}\right)=\frac{327}{13}-\left(\frac{15}{17}+\frac{47}{3}\right)\)
\(=\frac{327}{13}-\frac{844}{51}\)
\(=\frac{5705}{663}\)
\(\frac{5}{30}+\frac{15}{90}+\frac{250}{150}+\frac{350}{210}+\frac{45}{270}=\frac{1}{6}+\frac{1}{6}+\frac{5}{3}+\frac{5}{3}+\frac{1}{6}\)
\(=\frac{3}{6}+\frac{10}{3}\)
\(=\frac{1}{2}+\frac{10}{3}\)
\(=\frac{23}{6}\)
\(3\frac{1}{11}.\frac{27}{46}.1\frac{6}{17}.2\frac{4}{9}=\frac{34}{11}.\frac{27}{46}.\frac{23}{17}.\frac{22}{9}\)
\(=\frac{68}{9}.\frac{27}{34}\)
\(=6\)
17 tháng 10 2018
=\(\frac{2^{30}3^{16}.5^{50}.7+2^{30}.3^{15}.3^2.11.5^{48}}{11.2^{25}.2^4.5^4.3^{18}.5^{18}.5^{30}-2^{30}.5^{30}.5^{22}.3^{18}}\)
=\(\frac{2^{30}.3^{16}.5^{50}.7+2^{30}.3^{17}.11.5^{48}}{11.2^{29}.5^{52}.3^{18}-2^{30}.5^{52}.3^{18}}\)
=\(\frac{2^{30}.3^{16}.5^{48}.11\left(5^2.7+3\right)}{2^{29}.5^{52}.3^{18}.11\left(1-2\right)}\)
=\(\frac{2.\left(5^2.7+3\right)}{5^4.3^2\left(1-2\right)}\)
=\(\frac{2.178}{5^4.3^2.\left(-1\right)}\)
=\(\frac{356}{-5625}\)
Hk tốt
TL
4
17 tháng 8 2016
a ) \(-\frac{13}{30}+\frac{11}{20}-\frac{7}{15}\)
\(=-\frac{26}{60}+\frac{33}{60}-\frac{28}{60}\)
\(=\frac{-26+33-28}{60}=-\frac{7}{20}\)
b ) \(-\frac{5}{72}:\left(\frac{3}{8}.\frac{7}{9}\right)\)
\(=-\frac{5}{72}:\frac{3.7}{8.9}\)
\(=-\frac{5}{72}:\frac{7}{24}\)
\(=-\frac{5}{72}.\frac{24}{7}=-\frac{5}{21}\)
17 tháng 8 2016
a) \(\frac{-13}{30}+\frac{11}{20}-\frac{7}{15}=\frac{-26}{60}+\frac{33}{60}-\frac{28}{60}=-\frac{21}{60}=-\frac{7}{20}\)
b) \(\frac{-5}{72}:\left(\frac{3}{8}.\frac{7}{9}\right)=\frac{-5}{72}:\frac{7}{24}=-\frac{5}{21}\)
c) \(\frac{-23}{25}.\frac{10}{13}+\frac{-23}{25}.\frac{3}{13}+\frac{-27}{25}\)
\(=\frac{-23}{25}.\left(\frac{10}{13}+\frac{3}{13}\right)+\frac{-27}{25}\)
\(=\frac{-23}{25}+\frac{-27}{25}\)
\(=\frac{-50}{25}=-2\)
ND
6
\(\frac{11}{30}-\frac{9}{25}x\frac{15}{27}=\frac{11}{30}-\frac{3}{15}=\frac{11}{30}-\frac{6}{30}=\frac{5}{30}=\frac{1}{6}\)