BÀI 5 : CHO E=\(\frac{x^2+6x+9}{x^3+3x^2-27x+27}\). \(\left(\frac{x^2+6x+9}{x^3+3x^2-27x+27}+\frac{2}{3x}:\left(\frac{1}{x}+\frac{1}{3}\right)^2\right)\)F=\(\frac{3+x}{3-x}\) .\(\frac{x^2-6x+9}{9x^2}\).\(\left(\frac{3}{3-x}-\frac{9}{27+x^3}.\frac{x^2-3x+9}{3-x}\right)\)a, RÚT GỌN E VÀ...
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BÀI 5 : CHO
E=\(\frac{x^2+6x+9}{x^3+3x^2-27x+27}\). \(\left(\frac{x^2+6x+9}{x^3+3x^2-27x+27}+\frac{2}{3x}:\left(\frac{1}{x}+\frac{1}{3}\right)^2\right)\)
F=\(\frac{3+x}{3-x}\) .\(\frac{x^2-6x+9}{9x^2}\).\(\left(\frac{3}{3-x}-\frac{9}{27+x^3}.\frac{x^2-3x+9}{3-x}\right)\)
a, RÚT GỌN E VÀ F
