5*2*3*4+1*3=
1*3*2+1*4*5=
chu y * la nhan
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a: \(\left(x+\dfrac{1}{4}\right)+\left(3x-4\right)+2\left(x-3\right)=1\)
=>\(x+\dfrac{1}{4}+3x-4+2x-6=1\)
=>\(6x-\dfrac{39}{4}=1\)
=>\(6x=1+\dfrac{39}{4}=\dfrac{43}{4}\)
=>\(x=\dfrac{43}{4}:6=\dfrac{43}{24}\)
b: \(2\left(x-3\right)=3\left(x+2\right)-x+1\)
=>\(2x-6=3x+6-x+1\)
=>2x-6=2x+7
=>-6=7(vô lý)
c: \(x\left(x+3\right)+x\left(x-2\right)=2x\left(x-1\right)\)
=>\(x^2+3x+x^2-2x=2x^2-2x\)
=>3x-2x=-2x
=>3x=0
=>x=0
d: \(\left(x-1\right)\cdot3x-2\left(x+2\right)-2x=x\left(x-1\right)\)
=>\(3x^2-3x-2x-4-2x=x^2-x\)
=>\(3x^2-7x-4-x^2+x=0\)
=>\(2x^2-6x-4=0\)
=>\(x^2-3x-2=0\)
=>\(x=\dfrac{3\pm\sqrt{17}}{2}\)
\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)
\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)
\(-\frac{100}{33}+x=-\frac{6}{5}\)
\(x=\frac{302}{165}\)
cau 1: giai
tong so phan bang nhau la:
2+3=5[phan]
truong do co so hoc sinh nam la:
567:5x2=226.8[hoc sinh]
so hoc sinh nu co trong truong la:
567-226.8=340.2[hoc sinh]
Dap so:226.8 hoc sinh nam
340.2 hoc sinh nu
cau 2: giai
nua chu vi hinh chu nhat do la:
350:2=175[m]
tong so phan bang nhau la:
3+4=7[phan]
chieu rong hinh thua ruong chu nhat do la:
175:7x3=75[m]
chieu dai hinh thua ruong chu nhat do la:
175-75=100[m]
dien h thua ruong do la:
100x75=7500[m2]
Dap so:7500m2
cau 3:tinh gia tri cua bieu thuc
a,[5/3-4/5]x3/2=[25/15-12/15]x3/2=13/15x3/2=39/30=13/10
b,3/2+3/4:2/3=3/2+9/6=3/2+3/2=6/2=3
cau 4:tinh bang cach thuan tien nhat:
a,1/5+4/11+4/5+7/11=[4/11+7/11]+[4/5+1/5]=1+1=2
b,27x45-23x27-27x11=27x[45-23-11]=27x11=297
o cau1,2 ban can them so do vao
o cau1 ban them ngay sau giai
o cau2 ban them so do sau khi tinh nua chu vi
ban ko tra loi ho minh cau nay a
neu the minh ket ban kieu gi
\(\frac{2}{5}:\frac{3}{7}x\frac{3}{7}:\frac{2}{5}+1999=\)\(\frac{2}{5}x\frac{7}{3}x\frac{3}{7}x\frac{5}{2}+1999=\)\(\left(\frac{2x7x3x5}{5x3x7x2}\right)+1999=\)\(1+1999=2000\)
\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)\)\(=\left(\frac{2}{2}-\frac{1}{2}\right)\)\(x\left(\frac{3}{3}-\frac{1}{3}\right)\)\(x\left(\frac{4}{4}-\frac{1}{4}\right)\)\(x\left(\frac{5}{5}-\frac{1}{5}\right)\)\(=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x\frac{4}{5}=\)\(\frac{1x2x3x4}{2x3x4x5}=\frac{1x\left(2x3x4\right)}{\left(2x3x4\right)x5}=\frac{1}{5}\)\(.\)
2/5:3/7 nhân 3/7:2/5+1999
=2/5 nhân 7/3 nhân 3/7nhân 5/2+1999
=14/15 nhân 15/14+1999
=1+1999
=2000
(1-1/2) nhân (1-1/3) nhân (1-1/4) nhân (1-1/5)
=1/2 nhân 2/3 nhân 3/4 nhân 4/5
=24/120
=1/5
(217 + 417) x (314-312) x (24-42) = (217+417) x (314-312) x 0 = 0
152+53 = 1+125 = 126
5*2*3*4+1*3
=10*12+3
=120+3
=123
1*3*2+1*4*5
=3*2+4*5
=6+20
=26
k cho mình nha bạn
5*2*3*4+1*3=123
1*3*2+1*4*5=26