\(2\frac{2}{3}x+\frac{8}{3}=3\frac{1}{3}\)
Giúp mình nha. Cảm ơn !
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\(\frac{1}{7}-\frac{8}{7}:8-3:\frac{3}{4}.\left(-2\right)^2\)
=\(\frac{1}{7}-\frac{1}{7}-4.4\)
=0-16
=-16
\(\left(\frac{2}{3}-1\frac{1}{2}\right):\frac{4}{3}+\frac{1}{2}\)
=\(\left(\frac{2}{3}-\frac{3}{2}\right)\times\frac{3}{4}+\frac{1}{2}\)
=\(\frac{-5}{6}\times\frac{3}{4}+\frac{1}{2}\)
=\(\frac{-5}{8}+\frac{4}{8}\)
=\(\frac{-1}{8}\)
Ai thấy đúng thì *******
\(\left(\frac{2}{3}-1\frac{1}{2}\right):\frac{4}{3}+\frac{1}{2}\)
\(=\left(\frac{2}{3}-\frac{3}{2}\right):\frac{4}{3}+\frac{1}{2}\)
\(=\left(\frac{4}{6}-\frac{9}{6}\right):\frac{4}{3}+\frac{1}{2}\)
\(=\frac{-5}{6}:\frac{4}{3}+\frac{1}{2}\)
\(=\frac{-5}{6}.\frac{3}{4}+\frac{1}{2}\)
\(=\frac{-5}{8}+\frac{1}{2}\)
\(=\frac{-5}{8}+\frac{4}{8}\)
\(=\frac{1}{8}\)
<=> 3 - 1/6 + x = 2/3
<=> 17/6 + x = 2/3
<=> x = 2/3 - 17/6
=> x = -13/6
Vậy x = -13/6
\(3-\left(\frac{1}{6}-x\right)=\frac{2}{3}\)
\(\Rightarrow\frac{1}{6}-x=3-\frac{2}{3}\)
\(\Rightarrow\frac{1}{6}-x=\frac{7}{3}\)
\(\Rightarrow x=\frac{1}{6}-\frac{7}{3}\)
\(\Rightarrow x=\frac{-13}{6}\)
a) \(\Leftrightarrow2.\left(\frac{2.3^x}{3}+3^x.3^2\right)=2.3^6\left(2+3^3\right)\)
\(\Leftrightarrow2.\left(\frac{2.3^x+3.3^x.3^2}{3}\right)=2.3^6.29\)
\(\Leftrightarrow2.\left[\frac{3^x.\left(2+3.3^2\right)}{3}\right]=2.3^6.19\)
\(\Leftrightarrow2.3^{x-1}.29=2.3^6.29\Leftrightarrow3^{x-1}.29=\frac{2.3^6.29}{2}=3^6.29\Leftrightarrow3^{x-1}=\frac{3^6.29}{29}=3^6\)
\(\Leftrightarrow3^{x-1}=3^6\Leftrightarrow x-1=6\Leftrightarrow x=6+1=7\)
vậy x=7 . Chọn mình nha
mấy bài sao tương tự nếu ko biết thì nhắn tin mình chỉ típ nha
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{8}{12}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(x=\frac{10}{12}-\frac{1}{12}\)
\(x=\frac{9}{12}\) \(=\frac{3}{4}\)
<=> 5/6 - x = 1/12
<=> -x = 1/12 - 5/6
<=> -x = -3/4
=> x = 3/4
Vậy x = 3/4
8/3*x+8/3=10/3
8/3*(x+1)=10/3
x+1=5/4
x=1/4 okay
\(2\frac{2}{3}x+\frac{8}{3}=3\frac{1}{3}\)
\(\Rightarrow\frac{8}{3}x+\frac{8}{3}=\frac{10}{3}\)
\(\Rightarrow\frac{8}{3}.\left(x+1\right)=\frac{10}{3}\)
\(\Rightarrow x=\frac{10}{3}:\frac{8}{3}\)
\(\Rightarrow x=\frac{10}{3}.\frac{3}{8}\)
\(\Rightarrow x=\frac{5}{4}\)