426-{3.[152-(5-2)^2] +1} : 10
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\(426-\left\{3.\left[152-\left(5-2\right)^2\right]\right\}:10\\ =426-\left\{3.\left[152-3^2\right]\right\}:10\\ =426-\left\{3.\left[152-9\right]\right\}\\ =426-\left\{3.143\right\}\\ =426-429=-3\)
426-{3.[152-(5-2)^2] +1} : 10=383
1672+[49+(13-7)^3]=1937
a) (426 + x) : 5 = 120
(=) 426 + x = 120 :5
(=) 426 + x = 24
(=) x = 24 - 426
(=) x = - 402
Vậy x = - 402
b) 5844 : x -159 = 328
(=) 5844 : x = 328+ 159
(=) 5844 : x = 487
(=) x = 5844 : 487
(=) x = 12
Vậy x = 12
c) 32x + 1 = 27
(=) 32x = 27 -1
(=) 32x = 26
=> vô lý
vậy x thuộc tập hợp rỗng
d) (3x - 1)2 = 64
(=) (3x - 1)2 = 82
(=) 3x - 1 = 8
(=) 3x = 8 + 1
(=) 3x = 9
(=) x = 9 : 3
(=) x = 3
Vậy x = 3
( 426 + x ) : 5 = 120
( 426 + x ) = 600
x = 600 - 426
x = 174
b ) 5844 : x - 159 = 328
5844 : x = 328 + 159
5844 : x = 487
x = 5844 : 487
x = 12
d ) ( 3x - 1 ) 2 = 64
( 3x - 1 ) = 8
3x = 9
x = 3
c.\(\dfrac{3}{7}+\dfrac{5}{7}:x=\dfrac{1}{3}\)
\(\dfrac{5}{7}:x=\dfrac{1}{3}-\dfrac{3}{7}\)
\(\dfrac{5}{7}:x=-\dfrac{2}{21}\)
\(x=\dfrac{5}{7}:-\dfrac{2}{21}\)
\(x=-\dfrac{15}{2}\)
d.\(3\dfrac{1}{4}:\left|2x-\dfrac{5}{12}\right|=\dfrac{39}{16}\)
\(\left|2x-\dfrac{5}{12}\right|=3\dfrac{1}{4}:\dfrac{39}{16}\)
\(\left|2x-\dfrac{5}{12}\right|=\dfrac{4}{3}\)
\(\rightarrow\left[{}\begin{matrix}2x-\dfrac{5}{12}=\dfrac{4}{3}\\2x-\dfrac{4}{12}=-\dfrac{4}{3}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}2x=\dfrac{7}{4}\\2x=-\dfrac{11}{12}\end{matrix}\right.\) \(\rightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{11}{24}\end{matrix}\right.\)
A, \(\dfrac{4}{9}+x=\dfrac{5}{3}\)
\(x\)\(=\dfrac{5}{3}-\dfrac{4}{9}\)
\(x\)\(=\dfrac{11}{9}\)
B,\(\dfrac{3}{4}.x=\dfrac{-1}{2}\)
\(x=\dfrac{-1}{2}:\dfrac{3}{4}\)
\(x=\)\(\dfrac{-2}{3}\)
Tổng A có số số hạng là: (2019-1):2+1= 1010 số
Tổng A là: 1010.(2019+1):2=1020100
\(a,\frac{4}{5}+\frac{17}{25}\)
\(=\frac{20}{25}+\frac{17}{25}\)
\(=\frac{37}{25}\)
\(b,\frac{7}{3}-\frac{5}{6}\)
\(=\frac{14}{6}-\frac{5}{6}\)
\(=\frac{9}{6}\)
\(=\frac{3}{2}\)
\(c,1+\frac{2}{3}\)
\(=\frac{3}{3}+\frac{2}{3}\)
\(=\frac{5}{3}\)
a) 4/5 + 17/25
= 20/25 + 17/25
= 37/25
b) 7/3 - 5/6
= 14/6 - 5/6
= 9/6
= 3/2
c) 1 + 2/3
= 3/3 + 2/3
= 5/3
A. \(\frac{2}{5}\div\frac{2}{3}=\frac{2}{5}\times\frac{3}{2}=\frac{2\times3}{5\times2}=\frac{3}{5}\text{ }\)
B. \(\frac{4}{7}\div\frac{4}{5}=\frac{4}{7}\times\frac{5}{4}=\frac{4\times5}{7\times4}=\frac{5}{7}\)
C. \(\frac{1}{6}\div\frac{1}{3}=\frac{1}{6}\times\frac{3}{1}=\frac{3}{6}=\frac{1}{2}\)
D. \(\frac{1}{4}\div\frac{1}{8}=\frac{1}{4}\times\frac{8}{1}=\frac{8}{4}=2\)
\(=426-\left\{3\cdot\left(152-9\right)+1\right\}:10\)
\(=426-\left\{3\cdot143+1\right\}:10\)
=426-43
=383
=426-{3x(152-9)+1}:10
=426-43
=383