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a)
uses crt;
var i,n:integer;
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until n<100;
if n mod 2=0 then
begin
for i:=0 to n do
if i mod 2=0 then write(i:4);
end
else writeln(n,' khong la so chan');
readln;
end.
b)
uses crt;
var i,n:integer;
begin
clrscr;
repeat
write('Nhap n='); readln(n);
until n<100;
if n mod 2=1 then
begin
for i:=1 to n do
if i mod 2=1 then write(i:4);
end
else writeln(n,' khong la so le');
readln;
end.
c1:
#include <bits/stdc++.h>
using namespace std;
long long i,n,s;
int main()
{
cin>>n;
s=1;
for (i=1; i<=n; i++) s=s*i;
cout<<s;
return 0;
}
Câu 2:
#include <bits/stdc++.h>
using namespace std;
long long i,n,s;
int main()
{
cin>>n;
s=1;
for (i=1; i<=n; i++) if (i%2==0) s=s*i;
cout<<s;
return 0;
}
Câu 1:
Program HOC24;
var i,p: integer;
t: longint;
begin
write('Nhap P: '); readln(p);
t:=0;
for i:=1 to p do if i mod 2<>0 then t:=t+i;
write('Tong cac so le la: ',t);
readln
end.
Caua1:
program caumot;
begin
writeln('lop 8A chao ban!');
end.
Câu 2:
program cauhai;
int a,b,c :real;
begin
write('a='); readln(a);
write('b='); readln(b);
c= a+b;
write('Tong hai so a b la:',c);
end.
program sochan;
uses crt;
var a:integer;
begin
write('hay nhap a');
readln(a);
if a mod 2 = 0 then writeln(' a la so chan',a);
end.
uses crt;
var a:integer;
begin
clrscr;
write('Nhap a='); readln(a);
if a mod 2=0 then write(a);
readln;
end.
1. Uses crt;
var n,i: integer;
begin clrscr;
readln(n);
for i:=1 to n do write(i:3);
readln;
end.
2. Uses crt;
var n,i: integer;
begin clrscr;
readln(n);
for i:=1 to n do if(i mod 2 = 0) then write(i:3);
readln;
end.
uses crt;
var a:real;
begin
clrscr;
write('Nhap a='); readln(a);
if a=0 then writeln('Khong tim duoc so nghich dao')
else writeln('So nghich dao la: ',1/a:4:2);
readln;
end.
2:
#include <bits/stdc++.h>
using namespace std;
int main()
{
string st;
int a;
cin>>st;
cin>>a;
cout<<"Xin chao "<<st<<endl;
cout<<"Nam nay "<<st<<" "<<2021-a<<" tuoi";
return 0;
}