Tìm x : 486 : x – 126 : x = 6
x = 81
x = 21
x = 60
x = 2160
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486 : x - 126 : x = 6
x : ( 486 - 126 ) = 6
x : 360 = 6
x = 360 : 6
= x = 60
HT
a,486:x-126:x=6
=>(486-126):x=6
=>360:x=6
=>x=360:6
=>x=60
b,725:x+175:x=5
=>(725+175):x=5
=>900:x=5
=>x=900:5
=>x=180
486:x-126:x=6
(486-126):x=6
360:x=6
x=360:6
x=60
725:x+175:x=5
(725+175):x=5
900:x=5
x=900:5
x=180
( 486 - 126 ) : x = 6
360 : x = 6
x = 360 : 6
x = 60
:)))
\(486:x-126:x=6\)
\(\left(486-126\right):x=6\)
\(360:x=6\)
\(x=360:6\)
\(x=60\)
486 : X - 126 : = 6
(486 - 126) : X = 6
360 : X = 6
X = 360 : 6
X = 60
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a) 162 : 𝑥 + 216 : 𝑥 = 6
(162 + 216) : x = 6
378 : x = 6
x = 378 : 6
x = 63
b) 602 : x + 123 x 2 = 253
602 : x + 246 = 253
602 : x = 253 - 246
602 : x = 7
x = 602 : 7
x = 86
c) 486 : x - 126 :x = 6
(486-126) : x = 6
360 : x = 6
x = 360 : 6
x = 60
d) 725 : x + 175 : x = 5
(725 + 175) : x = 5
900 : x = 5
x = 900 : 5
x = 180
a)\(162:x+216:x=6\)
⇔\(\left(162+216\right):x=6\)
⇔\(378:x=6\)
⇔\(x=63\)
b)\(602:x+123.2=253\)
⇔\(602:x+246=253\)
⇔\(602:x=7\)
⇔\(x=86\)
c)\(486:x-126:x=6\)
⇔\(\left(486-126\right):x=6\)
⇔\(360:x=6\)
⇔\(x=60\)
d)\(725:x+175:x=5\)
⇔\(\left(725+175\right):x=5\)
⇔\(900:x=5\)
⇔\(x=180\)
\(a.162:x+216:x=6\) \(b.602:x+123x2=253\)
\(\left(162+216\right):x=6\) \(602:x+246=253\)
\(378:x=6\) \(602:x=253-246\)
\(x=378:6=63\) \(602:x=7\)
\(x=602:7=86\)
\(c.486:x-126:x=6\) \(d.725:x+175:x=5\)
\(\left(486-126\right):x=6\) \(\left(725+175\right):x=5\)
\(360:x=6\) \(900:x=5\)
\(x=360:6=60\) \(x=900:5=180\)
a.
\(\Leftrightarrow\sqrt[3]{3x-5}=\left(2x-3\right)^3+2x-3-\left(3x-5\right)\)
Đặt \(\left\{{}\begin{matrix}2x-3=a\\\sqrt[3]{3x-5}=b\end{matrix}\right.\)
\(\Rightarrow b=a^3+a-b^3\)
\(\Leftrightarrow a^3-b^3+a-b=0\)
\(\Leftrightarrow\left(a-b\right)\left(a^2+ab+b^2+1\right)=0\)
\(\Leftrightarrow a=b\)
\(\Leftrightarrow\sqrt[3]{3x-5}=2x-3\)
\(\Leftrightarrow3x-5=\left(2x-3\right)^3\)
\(\Leftrightarrow8x^3-36x^2+51x-22=0\)
\(\Leftrightarrow\left(x-2\right)\left(8x^2-20x+11\right)=0\)
\(\Leftrightarrow...\)
b.
\(\Leftrightarrow x^3-2x^2-\dfrac{5}{3}x+3x-2-\sqrt[3]{81x-8}=0\)
\(\Leftrightarrow x^3-2x^2-\dfrac{5}{3}x+\dfrac{\left(3x-2\right)^3-\left(81x-8\right)}{\left(3x-2\right)^2+\left(3x-2\right)\sqrt[3]{81x-8}+\sqrt[3]{\left(81x-8\right)^2}}=0\)
\(\Leftrightarrow x^3-2x^2-\dfrac{5}{3}x+\dfrac{27\left(x^3-2x^2-\dfrac{5}{3}x\right)}{\left(3x-2\right)^2+\left(3x-2\right)\sqrt[3]{81x-8}+\sqrt[3]{\left(81x-8\right)^2}}=0\)
\(\Leftrightarrow\left(x^3-2x^2-\dfrac{5}{3}x\right)\left(1+\dfrac{27}{\left(3x-2\right)^2+\left(3x-2\right)\sqrt[3]{81x-8}+\sqrt[3]{\left(81x-8\right)^2}}\right)=0\)
\(\Leftrightarrow x^3-2x^2-\dfrac{5}{3}x=0\)
486÷x-126÷x=6
(486-126) ÷ x = 6
360 ÷ x = 6
x = 360 ÷ 6
x = 60
Ta có(486-126)/x=6
Suy ra 360/x=6
Suy ra x=360/6
Suy ra x=60
Vậy x=60
Tìm x : 486 : x – 126 : x = 6
x = 81
x = 21
x = 60
x = 2160
\(x=60\)