X x 6 - 1996 = 2324
x =.......
x =.......
x =.......
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x x 6 - 1996 = 2324
x x 6 = 2324 + 1996
x x 6 = 4320
x = 4320 : 6
x = 720
dung thi tk nha
a) X x 3 = 3652
X= 3654:3
X = 1218
b) 2015 + X = 2324
X = 2324 – 2015
X = 309
(X -10/1994 -1) + (X-8/1996 - 1) + (X-6/1998 - 1)+ (X-4/2000 - 1) + (X-2/2002 - 1) = (X-2002/2 - 1) + (X-2000/4 - 1) + (X-1998/6 - 1) + (X-1996/8 - 1) + (X-1994/10 - 1)
=> x-2004/1994 + x-2004/1996 + x-2004/1998 + x-2004/2000 + x-2004/2002 = x-2004/2 + x-2004/4 + x-2004/6 + x-2004/8 + x-2004/1994
=> x-2004/1994 + x-2004/1996 + x-2004/1998 + x-2004/2000 + x-2004/2002 - x-2004/2 - x-2004/4 - x-2004/6 - x-2004/8 - x-2004/1994 = 0
=> (x - 2004)(1/994 + 1/1996 + 1/1998 + 1/2000 + 1/2002 + 1/2 + 1/4 + 1/6 + 1/8) = 0
Mà (1/994 + 1/1996 + 1/1998 + 1/2000 + 1/2002 + 1/2 + 1/4 + 1/6 + 1/8) \(\ne\)0
=> x - 2004 = 0
=> x = 2004
Vậy x = 2004
\(\left(\frac{x-10}{1994}-1\right)\)+\(\left(\frac{x-8}{1996}-1\right)\)+\(\left(\frac{x-6}{1998}-1\right)\)+\(\left(\frac{x-4}{2000}-1\right)\)+\(\left(\frac{x-2}{2002}-1\right)\)=\(\left(\frac{x-2002}{2}-1\right)\)+\(\left(\frac{x-2000}{4}-1\right)\)+\(\left(\frac{x-1998}{6}-1\right)\)+\(\left(\frac{x-1996}{8}-1\right)\)+\(\left(\frac{x-1994}{10}-1\right)\)
suy ra \(\frac{x-2004}{1994}\)+\(\frac{x-2004}{1996}\)+\(\frac{x-2004}{1998}\)+\(\frac{x-2004}{2000}\)+\(\frac{x-2004}{2002}\)=\(\frac{x-2004}{2}\)+\(\frac{x-2004}{4}\)+\(\frac{x-2004}{6}\)+\(\frac{x-2004}{8}\)+\(\frac{x-2004}{10}\)
suy ra \(\frac{x-2004}{1994}\)+\(\frac{x-2004}{1996}\)+\(\frac{x-2004}{1998}\)+\(\frac{x-2004}{2000}\)+\(\frac{x-2004}{2002}\)- \(\frac{x-2004}{2}\)- \(\frac{x-2004}{4}\)- \(\frac{x-2004}{6}\)- \(\frac{x-2004}{8}\)- \(\frac{x-2004}{10}\)=0
suy ra (x-2004) . ( \(\frac{1}{1994}\)+\(\frac{1}{1996}\)+\(\frac{1}{1998}\)+\(\frac{1}{2000}\)+\(\frac{1}{2002}\)-\(\frac{1}{2}\)-\(\frac{1}{4}\)-\(\frac{1}{6}\)- \(\frac{1}{8}\)- \(\frac{1}{10}\))=0
Vì \(\frac{1}{1994}\)+\(\frac{1}{1996}\)+\(\frac{1}{1998}\)+\(\frac{1}{2000}\)+\(\frac{1}{2002}\)-\(\frac{1}{2}\)-\(\frac{1}{4}\)-\(\frac{1}{6}\)- \(\frac{1}{8}\)- \(\frac{1}{10}\) khác 0
nên x-2004=0 suy ra x=2004
Số số hạng :
(1996-2):2+1=998(số)
Tách x trong ngoặc :
998x + ( 2 + 4 +6 + ...+1996) = 998000
998x + ( 998 x (1996+2):2) = 998000
998x + 997002 = 998000
998x = 998000-997002
998x=998
x=1
\(a)\)\(\left(x+2\right)+\left(x+4\right)+\left(x+6\right)+...+\left(x+1996\right)=998000\)
\(\Rightarrow\)\(x+2+x+4+x+6+...+x+1996=998000\)
\(\Rightarrow\)\(\left(x+x+...+x\right)+\left(2+4+6+...+1996\right)=998000\)
Từ 2 đến 1996 có số số hạng là:
\(\left(1996-2\right)\div2+1=998\)( số hạng )
Nên sẽ có \(998\)thừa số x:
Tổng 2 đến 1996 là:
\(\left(1996+2\right)\times998\div2=997002\)
Ta có:
\(998\times x+997002=998000\)
\(\Rightarrow\)\(998\times x=998000-997002\)
\(\Rightarrow\)\(998\times x=998\)
\(\Rightarrow\)\(x=998\div998\)
\(\Rightarrow\)\(x=1\)
X x 6 - 1996 = 2324
X x 6 =2324+1996
X x 6 =4320
x =4320:6
x =720
Xx6= 2324+1996
Xx6=4320
=> X=4320:6
X=720