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a) ( 75 - 3 2 - 12 )( 3 + 2 )
=(5 3 - 3 2 - 2 3 )( 3 + 2 )
=3( 3 - 2 )( 3 + 2 ) = 3
Ta có: \(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\)
\(=2\sqrt{3}+6\sqrt{3}+15\sqrt{3}-36\sqrt{3}\)
\(=-13\sqrt{3}\)
\(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\\ =2\sqrt{3}+6\sqrt{3}+15\sqrt{3}-36\sqrt{3}=-13\sqrt{3}\)
a: \(=5\cdot5\sqrt{3}-\dfrac{1}{3}\cdot3\sqrt{3}=24\sqrt{3}\)
b: \(=\dfrac{12\left(3+\sqrt{5}\right)}{4}=9+3\sqrt{5}\)
c: \(=3-\sqrt{5}+\sqrt{5}=3\)
a ) = 37.[ ( - 75 ) - 25 ] = 37 .( - 100 ) = - 3700
b ) = 36 + ( - 90 ) + ( - 8 ) = - 62
a)=37.(-75)+37.(-25)
=37.[(-75)+(-25)]
=37.(-100)
=-3700
mình nha
____Ngốc cuồng BTS____:
-75+(-49)+|-75|+49-12
=-75+(-49)+75+49-12
=[-75+(-49)]+(75+49)-12
=-124+124-12
=0-12
=-12
\(-75+\left(-49\right)+|-75|+49-12=-75-49+75+49-12\)
\(=\left[\left(75-75\right)+\left(49-49\right)\right]-12=0+0-12=-12\)
\(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\)
\(=2\sqrt{3}+6\sqrt{3}+15\sqrt{3}-36\sqrt{3}\)
\(=-13\sqrt{3}\)
5 7 − 7 5 − 1 2 − − 2 7 − 1 10 = − 24 35 − 1 2 − − 27 70 = − 24 35 − 31 35 = − 11 7
a.=18 : 9 + 5 .8
=2+40
=42
b. = -(12+42)
= -54
c. =53.25+53.75+27.18+27.82
=53.(25+75)+27.(18+82)
=53.100+27.100
=100.(53+27)
=100.80
=8000
d.{75+(-75)}+(-350)
=0+(-350)
=-350
a) 18 : 32 + 5 . 23
= 18 : 9 + 5 . 8
= 2 + 40
= 42
b) (-12) + (-42)
= -(12+42)
= - 54
c) 53.25 + 53.75 + 27.18 + 33.82
= 53.25 + 53.75 + 27 .18 + 27.82
= 53.(25+75) + 27.(18+82)
= 53.100 + 27.100
= 100.(53 + 27)
= 100. 80
= 8000
d) 75 + (-350) + (-75)
= 75 + (-75) + (-350)
= 0 + (-350)
= -350
Chúc bạn học tốt!
-7/23*75/97+75/97-11/23*75/97
=75/97*(-7/23+11/23)
=75/97*4/23
=300/2231
(3/8+ -1/4+5/12):2/3
=(9/24+ -6/24+10/24):2/3
=13/24/2/3
=13/16
ai h cho minh minh h lai cho
Ta có: \(\sqrt{75}-2\cdot\sqrt{12}+\sqrt{3}\)
\(=5\sqrt{3}-2\cdot2\sqrt{3}+\sqrt{3}\)
\(=6\sqrt{3}-4\sqrt{3}\)
\(=2\sqrt{3}\)