30:3 nhân 2
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\(a.20-\left[30-\left(5-1\right)^2\right]\) \(b.75-\left(3.5^2-4.2^3\right)\)
\(=20-\left[30-4^2\right]\) \(=75-\left(75-4.2^3\right)\)
\(=20-14=6\) \(=75-\left(75-32\right)\)
\(=75-43=32\)
Ta có :
a) 3 x 5 x 8/4 x 2 x 25 = 1500
b) 30 x 7 x 12/6 x 10 x 4 = 16800
Đáp số : a) 1500
: b) 16800
\(25\frac{2}{13}-\left(\frac{15}{17}+15\frac{2}{3}\right)=\frac{327}{13}-\left(\frac{15}{17}+\frac{47}{3}\right)\)
\(=\frac{327}{13}-\frac{844}{51}\)
\(=\frac{5705}{663}\)
\(\frac{5}{30}+\frac{15}{90}+\frac{250}{150}+\frac{350}{210}+\frac{45}{270}=\frac{1}{6}+\frac{1}{6}+\frac{5}{3}+\frac{5}{3}+\frac{1}{6}\)
\(=\frac{3}{6}+\frac{10}{3}\)
\(=\frac{1}{2}+\frac{10}{3}\)
\(=\frac{23}{6}\)
\(3\frac{1}{11}.\frac{27}{46}.1\frac{6}{17}.2\frac{4}{9}=\frac{34}{11}.\frac{27}{46}.\frac{23}{17}.\frac{22}{9}\)
\(=\frac{68}{9}.\frac{27}{34}\)
\(=6\)
\(x^3-6x^2-x+30\\=x^3+2x^2-8x^2-16x+15x+30\\=x^2(x+2)-8x(x+2)+15(x+2)\\=(x+2)(x^2-8x+15)\\=(x+2)(x^2-3x-5x+15)\\=(x+2)[x(x-3)-5(x-3)]\\=(x+2)(x-3)(x-5)\\Toru\)
\(x^3-6x^2-x+30\)
\(=x^3-3x^2-3x^2+9x-10x+30\)
\(=x^2\left(x-3\right)-3x\left(x-3\right)-10\left(x-3\right)\)
\(=\left(x^2-3x-10\right)\left(x-3\right)\)
\(=\left(x^2-5x+2x-10\right)\left(x-3\right)\)
\(=\left(x\left(x-5\right)+2\left(x-5\right)\right)\left(x-3\right)\)
\(=\left(x+2\right)\left(x-5\right)\left(x-3\right)\)
bằng 20 nha chúc mọi người thi tốt
Đáp án 20 nhá