Tìm hai số tự nhiên a và b (18 < a < b) có BCNN bằng 270 và ƯCLN bằng 18
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a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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52542000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 | 542454550212.100000000000000000000000000000000000000000000000000000000000000000000000000000 |
Ta có : BCNN(a,b) . ƯCLN(a;b) = a.b
=> a.b = 270 . 18
=> a.b = 4860 (1)
Vì ƯCLN(a;b) = 18
=> Đặt\(\hept{\begin{cases}a=18m\\b=18n\end{cases}}\left(m;n\inℕ^∗;\text{ƯCLN(m;n)}=1\right)\)(2)
Thay (2) vào (1) ta có
=> 18m.18n = 4860
=> mn = 15
Với \(m;n\inℕ^∗\)ta có : 15 = 3.5 = 1.15
=> Lập bảng xét 4 trường hợp ta có :
m | 1 | 15 | 3 | 5 |
n | 15 | 1 | 5 | 3 |
a | 18 | 270 | 54 | 90 |
b | 270 | 18 | 90 | 54 |
Vậy các cặp số (a;b) thỏa mãn bài toán là : (18 ; 270) ; (270;18) ; (54;90) ; (90 ; 54)
\(ab=\left(a,b\right).\left[a,b\right]=18.270=4860\)
Đặt \(a=18m,b=18n\), \(1< m< n,\left(m,n\right)=1\).
\(ab=18m.18n=324mn=4860\Leftrightarrow mn=15\)
suy ra \(\hept{\begin{cases}m=3\\n=5\end{cases}}\Rightarrow\hept{\begin{cases}a=54\\b=90\end{cases}}\)