Héo mì ! Giúp e vs e cần gấp !
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MA
2
23 tháng 12 2021
g: \(=\dfrac{x^2+2x-x^2-4x-2x+4}{x\left(x-2\right)\left(x+2\right)}=\dfrac{-4x+4}{x\left(x-2\right)\left(x+2\right)}\)
h: \(=\dfrac{2x^2+1-x^2+1-x^2+x-1}{\left(x+1\right)\left(x^2-x+1\right)}\)
\(=\dfrac{x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{1}{x^2-x+1}\)
23 tháng 12 2021
\(e,=\dfrac{1}{x-1}-\dfrac{2x}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{x^2-2x+1}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{\left(x-1\right)^2}{\left(x^2+1\right)\left(x-1\right)}=\dfrac{x-1}{x^2+1}\\ f,=\dfrac{3x-1}{2\left(3x+1\right)}+\dfrac{3x+1}{2\left(3x-1\right)}-\dfrac{6x}{\left(3x-1\right)\left(3x+1\right)}\\ =\dfrac{9x^2-6x+1+9x^2+6x+1-12x}{2\left(3x-1\right)\left(3x+1\right)}=\dfrac{2\left(3x-1\right)^2}{2\left(3x-1\right)\left(3x+1\right)}=\dfrac{3x-1}{3x+1}\)
\(g,=\dfrac{x}{x\left(x-2\right)}-\dfrac{x^2+4x}{x\left(x-2\right)\left(x+2\right)}-\dfrac{2}{x\left(x+2\right)}\\ =\dfrac{x^2+2x-x^2-4x-2x+4}{x\left(x-2\right)\left(x+2\right)}=\dfrac{-4x+4}{x\left(x-2\right)\left(x+2\right)}\\ h,=\dfrac{2x^2+1-x^2+1-x^2+x-1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{1}{x^2-x+1}\)
TN
1
DT
Đỗ Thanh Hải
CTVVIP
11 tháng 8 2021
1 I wish my students studied hard
2 I wish I could come to the party
3 I wish my grandparents didn't live too far from me
4 Nga wished she were in HN now
5 This room is cleaned everyday
TA
23 tháng 12 2021
Bài I
\(1,=x\left(x-y\right)\\ 2,=x\left(y+1\right)+y+1=\left(x+1\right)\left(y+1\right)\\ 3,=x\left(x^2-2x-5x+10\right)=x\left(x-2\right)\left(x-5\right)\)
Bài II
\(1,=x-x^2+x^2-x-2=-2\\ 2,\Leftrightarrow x^2+6x+9-x^2=45\\ \Leftrightarrow6x=36\Leftrightarrow x=6\)
Bài III
\(1,A=\dfrac{4-9}{3\left(2+5\right)}=\dfrac{-5}{3\cdot7}=-\dfrac{5}{21}\\ 2,B=\dfrac{x^2-3x+2x^2+6x-3x^2-9}{\left(x-3\right)\left(x+3\right)}=\dfrac{3\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{3}{x+3}\\ 3,P=AB=\dfrac{\left(x-3\right)\left(x+3\right)}{3\left(x+5\right)}\cdot\dfrac{3}{x+3}=\dfrac{x-3}{x+5}=1-\dfrac{8}{x+5}\in Z\\ \Leftrightarrow x+5\inƯ\left(8\right)=\left\{-8;-4;-2;-1;1;2;4;8\right\}\\ \Leftrightarrow x\in\left\{-13;-9;-7;-6;-4;-1;3\right\}\)
SV
Sinh Viên NEU
CTVVIP
29 tháng 10 2023
Gửi bạn nhé
Sharing household chores is an essential aspect of maintaining a harmonious and balanced household. By dividing the responsibilities among family members, it not only lightens the workload but also fosters a sense of cooperation and unity. Sharing chores teaches valuable life skills and instills a sense of responsibility in everyone involved. It promotes equality and fairness, ensuring that no one person is burdened with all the tasks. Moreover, sharing household chores allows for more free time and relaxation, enabling family members to spend quality time together and pursue personal interests. Ultimately, sharing household chores is a fundamental component of a well-functioning and happy home