Tìm x:
x x 8 + 25 = 81
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a) 612 - 256 : X = 589
256 : X = 612 - 589
256 : X = 23
X = 256 : 23
X = 256/23
\(\frac{x+1}{2}=\frac{8}{x+1}\Rightarrow\left(x+1\right)^2=8.2\)
=>(x+1)2=16
=>x+1=\(\sqrt{16}\)
=>x+1=4
=>x=3
\(X:\dfrac{3}{9}=\dfrac{7}{8}\)
\(X=\dfrac{7}{8}\times\dfrac{3}{9}\)
\(X=\dfrac{21}{72}\)
\(\left(X-21\times13\right):11=30\)
\(X-273=330\)
\(X=603\)
`x:3/9=7/8`
`x=7/8xx3/9`
`x=7/24`
`-------------`
`(x-21xx13):11=30`
`(x-273):11=30`
`x-273=30xx11`
`x-273=330`
`x=330-273`
`x=57`
\(x=\dfrac{4}{5}\times\dfrac{4}{3}\)
\(x=\dfrac{16}{15}\)
-----------------------
\(x=\dfrac{5}{9}\times\dfrac{3}{8}\)
\(x=\dfrac{5}{24}\)
\(\Leftrightarrow\left(x+2\right)^2\cdot\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=-1\end{matrix}\right.\)
Bài 2:
Ta có: \(x\left(x-4\right)-x^2+8=0\)
\(\Leftrightarrow x^2-4x-x^2+8=0\)
\(\Leftrightarrow-4x=-8\)
hay x=2
a: \(\Leftrightarrow x\left(x-\sqrt{3}\right)\left(x+\sqrt{3}\right)=0\)
hay \(x\in\left\{0;\sqrt{3};-\sqrt{3}\right\}\)
b: \(=\dfrac{x^3-3x^2+6x-8}{x-2}=\dfrac{x^2-2x-x^2+2x+4x-8}{x-2}=x^2-x+4\)