55x1+256- 352=?
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a,=(202-54)(202+54)+256*352=248.*256+256*352=256*(248+352)=256*600=256*6*100=153600
b. làm tương tự
c,=5/(1+2+...+10)=5.\(\frac{10.\left(10+1\right)}{2}\)=275
(ta có công thức 1+2+...+n=\(\frac{n.\left(n+1\right)}{2}\) dễ dàng chứng minh)
10-10+20-25+55x1
=10-10+20-25+55
=0+20-25+55
=20-25+55
=-5+55
=50
320-4x+43=352
4x+64=320-352
4x+64=-32
4x=-32-64
4x=-96
x=-96:4
x=-24
2)Tính nhanh:
a)\(202^2-54^2+256.352\)
\(=\left(202-54\right)\left(202+54\right)+256.352\)
\(=148.256+256.352\)
\(=256\left(148+352\right)\)
\(=256.500\)
\(=128000\)
b)\(621^2-769.373-148^2\)
\(=621^2-148^2-769.373\)
\(=\left(621-148\right)\left(621+148\right)-769.373\)
\(=473.769-769.373\)
\(=769\left(473-373\right)\)
\(=769.100\)
\(=76900\)
\(a,\left(x-y+4\right)^2-\left(2x+3y-1\right)^2\)
\(=\left(x-y+4-2x-3y+1\right)\left(x-y+4+2x+3y-1\right)\)
\(=\left(-x-4y+5\right)\left(3x+2y+3\right)\)
\(b,9x^2+90x+225-\left(x-7\right)^2\)
\(=9\left(x^2+10x+25\right)-\left(x-7\right)^2\)
\(=9\left(x+5\right)^2-\left(x-7\right)^2\)
\(=\left[3\left(x+5\right)\right]^2-\left(x-7\right)^2\)
\(=\left(3x+15\right)^2-\left(x-7\right)^2\)
\(=\left(3x+15-x+7\right)\left(3x+15+x-7\right)\)
\(=\left(2x+22\right)\left(4x+8\right)\)
\(=2\left(x+11\right).4\left(x+2\right)\)
\(=8\left(x+2\right)\left(x+11\right)\)
\(c,49\left(y-4\right)^2-9y^2-36y-36\)
\(=\left\{\left[7\left(y-4\right)\right]^2-\left(3y\right)^2\right\}-\left(36y+36\right)\)
\(=\left(7y-28-3y\right)\left(7y-28+3y\right)-36\left(y+1\right)\)
\(=\left(4y-28\right)\left(10y-28\right)-36\left(y+1\right)\)
\(=4\left(y-7\right)2\left(5y-14\right)-36\left(y+1\right)\)
\(=8\left(y-7\right)\left(5y-14\right)-36\left(y+1\right)\)
\(=4\left[2\left(y-7\right)\left(5y-14\right)-9\left(y+1\right)\right]\)
mk ko chắc là câu này mk lm đg
\(d,x^2-5x-14\)
\(=x^2+2x-7x-14\)
\(=x\left(x+2\right)-\left(7x+14\right)\)
\(=x\left(x+2\right)-7\left(x+2\right)\)
\(=\left(x+2\right)\left(x-7\right)\)
\(A=256-\dfrac{256}{2}-\dfrac{256}{2^2}-\dfrac{256}{2^3}-.......-\dfrac{256}{2^9}\)
\(\Leftrightarrow A=256\left(1-\dfrac{1}{2}-\dfrac{1}{2^2}-\dfrac{1}{2^3}-.....-\dfrac{1}{2^9}\right)\)
Đặt \(B=\dfrac{1}{2}-\dfrac{1}{2^2}-\dfrac{1}{2^3}-.....-\dfrac{1}{2^9}\)
\(\Leftrightarrow2B=1-\dfrac{1}{2}-\dfrac{1}{2^2}-.....-\dfrac{1}{2^8}\)
\(\Leftrightarrow2B-B=1-\dfrac{1}{2^9}\)
\(\Leftrightarrow B=1-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=256\left(1-\dfrac{1}{2^9}\right)\)
\(\Leftrightarrow A=256-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=2^8-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=\dfrac{2^{17}}{2^9}-\dfrac{1}{2^9}\)
\(\Leftrightarrow A=\dfrac{2^{17}-1}{2^9}\)
Vậy \(\Leftrightarrow A=\dfrac{2^{17}-1}{2^9}\)
Chúc bạn học tốt >w<
TL:
= 311 - 352 = ( - 41 )
nếu đây là toán 3 thì đề sai nha
_HT_
55 x 1 + 256 - 356 = -41