giup tui can gap
tinh
( -3/5 )^14 . ( 3/5 )^13 =
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1/(-37) +14+26+37
=[(-37)+37] +(14+26)
= 0 + 40
= 40
2/(-24) +6 +10+24
=[(-24)+24] +(10+6)
= 0 +16
=16
3/15+23+9+(-25) +9+(-23)
=[(-23)+23] +[(-25)+15] +(9+9)
= 0 + (-10) +18
= 0 + 8
= 8
4/60 +33 +(-50) +(-33)
=[(-33)+33]+[60 +(-50)]
= 0 + 10
= 10
5/(-16)+ (-209) + (-14) +209
=[(-209)+209] +[(-16)+(-14)]
= 0 +(-30)
= -30
6/(-12) +(-13)+36 +(-11)
=[(-12) +(-11)] +[ 36+(-13)]
= (-23) + 23
= 0
Chúc bn hok tốt !!!
1, (-37)+14+26+37=[(-37)+37]+14+26=0+40=40
2, (-24)+6+10+24=[(-24)+24]+6+10=0+16=16
3 , 15+23+(-25)+(-23)=[15+(-25)]+[23+(-23)]=-10
4, 60+33+(-50)+(-33)= [60+(-50)]+[33+(-33)]=10
5, (-16)+(-209)+(-14)+209=[(-16)+(-14)]+[(-209)+209]=-30
6, (-12)+(-13)+36+(-11)=[(-12)+(-11)]+[(-13)+36]=(-23)+23=0
S= 2-1-2-3-4-....-201-202
= 2-(1+2+3+4+....+202)
=2- (202:2)( 202+1)
= 2- 101.203
\(M=1+\dfrac{1}{5}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{3}+\dfrac{3}{15}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{99\cdot101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{101}\right)=\dfrac{3}{2}\cdot\dfrac{100}{101}=\dfrac{150}{101}\)
\(45-/x+14/=2^3.3\)
\(=>45-/x+14/=24\)
\(TH1:x\ge14=>/x+14/=\left(x+14\right)\)
\(=>45-/x+14/=24\)
\(=>45-\left(x+14\right)=24\)
\(=>x+14=45-24\)
\(=>x=21-14\)
\(=>x=7\)
\(TH2:x< 14=>/x+14/=-\left(x+14\right)=-x-14\)
\(=>45-/x+14/=24\)
\(=>45+x-14=24\)
\(=>45-x=24+14\)
\(=>x=45-38\)
\(=>x=7\)
Vậy...
\(A=\left(\dfrac{1}{3}+\dfrac{3}{5}+\dfrac{1}{15}\right)-\left(\dfrac{3}{4}+\dfrac{2}{9}+\dfrac{1}{36}\right)+\dfrac{1}{64}\)
\(=\dfrac{5+9+1}{15}-\dfrac{27+8+1}{36}+\dfrac{1}{64}\)
=1/64
:)) cái đề ác nhờ, cộng hay nhân hay trừ ấy ( tôn trọng ý kiến lấy nhân nhá :)
\(\left(-\frac{3}{5}\right)^{14}\left(\frac{3}{5}\right)^{13}=\left(\frac{3}{5}\right)^{14}\left(\frac{3}{5}\right)13=\left(\frac{3}{5}\right)^{182}\)
bn oi dau cham la nhan ma