Thực hiện phép tính sau :
A = \(\left(\frac{-2}{3}+1\frac{1}{4}-\frac{1}{6}\right)\)
B = \(\frac{13}{15}\).0,25.3 + \(\left(\frac{8}{15}-1\frac{19}{60}\right)\) : \(1\frac{23}{24}\)
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\(A=\left(\frac{-2}{3}+1\frac{1}{4}-\frac{1}{6}\right).\frac{-12}{5}\)
=\(\left(\frac{-8+15-2}{12}\right).\frac{-12}{5}\)\(=\frac{5}{12}.\frac{-12}{5}=-1\)
a/ (-3,2).\(\frac{-15}{64}\)+(0,8-2\(\frac{4}{5}\)):1\(\frac{23}{24}\)
=(\(\frac{-16}{5}\)).\(\frac{-15}{64}\)+(\(\frac{4}{5}\)-\(\frac{14}{5}\)):\(\frac{47}{24}\)
=(\(\frac{-16}{5}\)).\(\frac{-15}{64}\)+(-2):\(\frac{47}{24}\)
= \(\frac{3}{4}\)+\(\frac{-48}{47}\)
=\(\frac{-51}{188}\)
b/ 1\(\frac{13}{15}\).3.(0,5)\(^2\).3+(\(\frac{8}{15}\)-1\(\frac{19}{60}\)):1\(\frac{23}{24}\)
= \(\frac{28}{15}\).3.\(\frac{1}{4}\).3+(\(\frac{8}{15}\)-\(\frac{79}{60}\)):\(\frac{47}{24}\)
= \(\frac{28}{15}\).3.\(\frac{1}{4}\).3+(\(\frac{-47}{60}\)):\(\frac{47}{24}\)
= \(\frac{28}{5}\).\(\frac{1}{4}\).3+(\(\frac{-47}{60}\)):\(\frac{47}{24}\)
= \(\frac{7}{5}\).3+(\(\frac{-47}{60}\)):\(\frac{47}{24}\)
= \(\frac{21}{5}\)+(\(\frac{-47}{60}\)):\(\frac{47}{24}\)
= \(\frac{21}{5}\)+(\(\frac{-2}{5}\))
= \(\frac{19}{5}\)
mk làm hơi dài dòng chút
CHÚC BẠN HỌC TỐT
\(A=-\frac{2}{3}+1\frac{1}{4}-\frac{1}{6}=-\frac{2}{3}+\frac{5}{4}-\frac{1}{6}=\frac{5}{12}\)
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right)\div1\frac{23}{24}\)
\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right)\div\frac{47}{24}\)
\(B=\frac{13}{20}-\frac{47}{60}\cdot\frac{24}{47}\)
\(B=\frac{13}{20}-\frac{2}{5}=\frac{1}{4}\)