\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\) \(\left(-\frac{1}{3}\right)^3\times x=\frac{1}{81}\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\) \(\left(x+\frac{1}{2}\right)^4=\frac{16}{81}\)
a)
\(x=\left(\frac{3}{7}\right)^7:\left(\frac{3}{7}\right)^5\)
\(x=\left(\frac{3}{7}\right)^2=\frac{9}{49}\)
b)
\(-\frac{1}{27}\cdot x=\frac{1}{81}\)
\(x=\frac{1}{81}:\left(-\frac{1}{27}\right)\)
\(x=-\frac{1}{3}\)
c)
\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(x-\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{1}{2}=\frac{5}{6}\)
d)
\(\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)
\(\orbr{\begin{cases}x+\frac{1}{2}=\frac{2}{3}\\x+\frac{1}{2}=\frac{-2}{3}\end{cases}}\)
\(\orbr{\begin{cases}x=\frac{2}{3}-\frac{1}{2}=\frac{1}{6}\\x=-\frac{2}{3}-\frac{1}{2}=-\frac{7}{6}\end{cases}}\)
Sửa lại câu a : ( nhìn sai số )
\(\frac{3^5}{5^5}\cdot x=\frac{3^7}{7^7}\)
\(x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)
\(x=\frac{3^7}{7^7}\cdot\frac{5^5}{3^5}\)
\(x=\frac{5^5\cdot3^2}{7^7}\)
\(x=\frac{28125}{823453}\)