Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1
N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)
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\(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}=\frac{41}{36}>\frac{36}{36}=1\)
Vậy P > 1.
1.y+17,28=17,28
=>y=0
2.18/9x y=2 (chịu)
3.y:6=0
=>y=0
4.\(5\frac{2}{8}:y=5\frac{2}{8}\)
=>\(\frac{5}{4}:y=\frac{5}{4}\)
=>y=1
Nhớ k mk nha
\(\frac{6}{2.5}+\frac{6}{5.8}+\frac{6}{8.11}+...+\frac{6}{299.302}\)
\(=2\left(\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+..+\frac{3}{299.302}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+...+\frac{1}{299}-\frac{1}{302}\right)\)
\(=2\left(\frac{1}{2}-\frac{1}{302}\right)=2.\frac{75}{151}=\frac{150}{151}\)
\(A=\frac{54.107-53}{53.107+54}=\frac{\left(53+1\right).107-53}{53.107+54}\)
\(=\frac{53.107+107-53}{53.107+54}=\frac{53.107+54}{53.107+54}=1\)
\(B=\frac{135.269-133}{134.269+135}=\frac{\left(134+1\right)269-133}{134.269+135}\)
\(=\frac{134.269+269-133}{134.269+135}=\frac{134.269+136}{134.269+135}>1\)
\(\Rightarrow B>A\)