cho đoạn thẳng AB và trung điểm M của nó.lấy điểm O thuộc tia đối của tia BA(O khác B).hãy so sanh OM với trung bình cộng của hai đoạn thẳng OA,OB.
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Ta có:
2OM=OM+OM=(OA+AM)+(OB−BM)=OA+OB+(AM−BM)2OM=OM+OM=(OA+AM)+(OB−BM)=OA+OB+(AM−BM)
Vì M là trung điểm AB
=> AM=BM
=> 2OM=OA+OB2OM=OA+OB
=> OM=OA+OB2
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