10 - (x – 3): 2 = 72 – 110
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\(\Rightarrow10-\left(x-3\right):2=49-1=48\\ \Rightarrow\left(x-3\right):2=-38\\ \Rightarrow x-3=-76\\ \Rightarrow x=-73\)
\(10-\left(x-3\right):2=7^2-1^{10}\)
\(\Rightarrow10-\left(x-3\right):2=48\)
\(\Rightarrow\left(x-3\right):2=-38\)
\(\Rightarrow x-3=-76\Rightarrow x=-73\)
a: x-56:4=16
nên x-14=16
hay x=30
b: \(101+\left(36-4x\right)=105\)
\(\Leftrightarrow36-4x=4\)
hay x=8
Vì a: x-56:4=16
=>x-14=16
Hay:x=30
Vì b: 101+(36−4x)=105101+(36−4x)=105
⇔36−4x=4⇔36−4x=4
Hay:x=8
Vậy x={30:8}
Nếu sai thì thui nhá,đừng chửi mình!
\(\Leftrightarrow4\left(x-3\right)=49-1=48\Leftrightarrow x-3=12\Leftrightarrow x=15\)
\(4\left(x-3\right)=7^2-1^{10}\)
\(4\left(x-3\right)=49-1\)
\(4\left(x-3\right)=48\)
\(\left(x-3\right)=48:4\)
\(x-3=12\)
\(x=15\)
- dễ mà VD : tách 1/30 thành 1/5.6 + 1/6.7 + 1/7.8 + 1/8.9 + 1/9.10 + 1/10.11 +1/11.12 - x =2/3
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
Ta có:
1/30+1/42+1/56+1/72+1/90+1/110+1/132 -x = 2/3
=>1/(5.6) + 1/(6.7) + 1/(7.8) + (1/8.9) + 1/(9.10) + 1/(10.11) + 1/(11.12) - x = 2/3
=>1/5-1/6+1/6-1/7+...+1/11-1/12 - x = 2/3
=>1/5-1/12 - x = 2/3
=>7/60 - x = 2/3
=> x = 7/60 - 2/3
=> x = -11/20
Bài làm:
\(\frac{3}{200}-\frac{3}{110}-\frac{3}{90}-\frac{3}{72}-\frac{3}{56}-...-\frac{3}{2}\)
\(=\frac{3}{200}-3\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{110}\right)\)
\(=\frac{3}{200}-3\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{10.11}\right)\)
\(=\frac{3}{200}-3\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{10}-\frac{1}{11}\right)\)
\(=\frac{3}{200}-3\left(1-\frac{1}{11}\right)\)
\(=\frac{3}{200}-\frac{30}{11}=-\frac{5967}{2200}\)
Học tốt!!!!