17+58*12/12=
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a) 5 8 + 3 17 + 4 18 + 20 − 17 + − 2 9 + 21 56
= 5 8 + 3 17 + 2 9 + − 20 17 + − 2 9 + 3 8 = 5 8 + 3 8 + 3 17 + − 20 17 + 2 9 + − 2 9 = 1 + − 1 + 0 = 0
b) − 2 11 + 6 7 + 1 2 + − 9 11 + 1 7
= − 2 11 + − 9 11 + 6 7 + 1 7 = − 1 + 1 = 0
58 + 26 + 4 = 88
78 + 9 + 12 = 99
35 + 15 - 10 = 40
60 - 10 + 17 = 67
a) \(36.\left(-57\right)-57.64\)
\(=36.\left(-57\right)+\left(-57\right).64=\left(-57\right).\left(36+64\right)\)
\(=\left(-57\right).100=-5700\)
b)\(32.\left(-17\right)+\left(-18\right).17-50.13\)
\(=\left(-32\right).17+\left(-18\right).17-50.13\)
\(=17.\left(-32-18\right)-50.13=17.\left(-50\right)+\left(-50\right).13\)
\(=\left(-50\right).\left(17+13\right)=\left(-50\right).30=-150\)
c)\(-\left(-35\right)+12-|-35|-42\)
\(=35+12-35-42=12-42=-30\)
d)\(\left(-15-12\right):\left(-3\right)^2+5-13.\left(-2\right)+\left(-64\right):2^3\)
\(=-27:9+5+26-64:8=-3+5+26-8=20\)
e)\(\left(135-35\right).\left(-37\right)+37.\left(-42-58\right)=100.\left(-37\right)+37.\left(-100\right)\)
\(=\left(-100\right).37+37.\left(-100\right)=\left(-100\right).\left(37+37\right)\)
\(=\left(-100\right).74=-7400\)
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\(\dfrac{x-90}{10}+\dfrac{x-76}{12}+\dfrac{x-58}{14}+\dfrac{x-36}{16}+\dfrac{x-15}{17}=15\)
\(\Leftrightarrow\dfrac{x-90}{10}-1+\dfrac{x-76}{12}-2+\dfrac{x-58}{14}-3+\dfrac{x-36}{16}-4+\dfrac{x-15}{17}-5=0\)
\(\Leftrightarrow\dfrac{x-100}{10}+\dfrac{x-100}{12}+\dfrac{x-100}{14}+\dfrac{x-100}{16}+\dfrac{x-100}{17}=0\)
\(\Leftrightarrow\left(x-100\right)\left(\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{14}+\dfrac{1}{16}+\dfrac{1}{17}\right)=0\)
\(\Leftrightarrow x-100=0\) (do \(\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{14}+\dfrac{1}{16}+\dfrac{1}{17}\ne0\))
\(\Leftrightarrow x=100\)
17+58*12/12= 17 + 58* 1=17 +58 =75