Tìm x
\(\frac{x}{15}\) = \(\frac{3}{5}\) + \(\frac{-2}{3}\)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
A
25 tháng 6 2018
\(x-\frac{3}{4}-x.\frac{2}{3}+x:\frac{1}{2}-x:\frac{2}{5}=\frac{11}{4}\)
\(x-x.\frac{2}{3}+x.2-x.\frac{5}{2}=\frac{11}{4}+\frac{3}{4}\)
\(x\left(1-\frac{2}{3}+2-\frac{5}{2}\right)=\frac{7}{2}\)
\(x.\frac{-1}{6}=\frac{7}{2}\)
\(x=\frac{7}{2}:-\frac{1}{6}\)
\(x=-21\)
Vậy \(x=-21\)
15 tháng 3 2019
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
NP
2
BA
18 tháng 9 2019
\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{2}{3}+\frac{2}{5}\right|\)
\(\Rightarrow-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{4}{15}\right|\).
\(\Rightarrow-\frac{4}{15}=\pm\left(-\frac{22}{15}x+\frac{1}{3}\right)\)
\(\Rightarrow\orbr{\begin{cases}-\frac{22}{15}x+\frac{1}{3}=-\frac{4}{15}\\-\left(-\frac{22}{15}x+\frac{1}{3}\right)=-\frac{4}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{9}{22}\\x=\frac{1}{22}\end{cases}}\)
18 tháng 9 2019
༃•๖ۣۜLãσ ๖ۣۜHạ¢ Em bị nhầm dạng toán này rồi. Khi ẩn x ở trong dấu giá trị tuyệt đối mình mới chia hai trường hợp em nhé!
Bài giải:
\(-\frac{22}{15}x+\frac{1}{3}=\left|-\frac{4}{15}\right|\)
\(-\frac{22}{15}x+\frac{1}{3}=\frac{4}{15}\)
\(-\frac{22}{15}x=\frac{4}{15}-\frac{1}{3}\)
\(-\frac{22}{15}x=-\frac{1}{15}\)
\(\frac{22x}{15}=\frac{1}{15}\)
\(x=\frac{1}{22}\)
KT
27 tháng 1 2018
a) \(\frac{x}{5}=\frac{2}{3}\)
\(\Rightarrow\)\(x=\frac{2.5}{3}=\frac{10}{3}\)
Vậy....
b) \(\frac{x+3}{15}=\frac{1}{5}\)
\(\Leftrightarrow\)\(5\left(x+3\right)=15\)
\(\Leftrightarrow\)\(x+3=3\)
\(\Leftrightarrow\)\(x=0\)
Vậy....
30 tháng 5 2015
\(\Rightarrow\left(\frac{7}{3}:x-\frac{2}{3}\right):\frac{7}{4}=-\frac{17}{5}-\frac{10}{9}\Rightarrow\left(\frac{7}{3}:x-\frac{2}{3}\right):\frac{7}{4}=-\frac{203}{45}\Rightarrow\frac{7}{3}:x-\frac{2}{3}=-\frac{1421}{180}\Rightarrow\frac{7}{3}:x=-\frac{1301}{180}\Rightarrow x=-\frac{420}{1301}\)
17 tháng 7 2016
a, \(\frac{1}{6}x+\frac{1}{10}-\frac{4}{15}x+1=0\)
\(\Leftrightarrow-\frac{1}{10}x=-\frac{11}{10}\)
\(\Leftrightarrow x=11\)
b,\(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(-\frac{1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
\(\Leftrightarrow\frac{1}{7}x-\frac{2}{7}=0\)hoặc \(-\frac{1}{5}x+\frac{3}{5}=0\)hoặc \(\frac{1}{3}x+\frac{4}{3}=0\)
+) \(\frac{1}{7}x-\frac{2}{7}=0\Leftrightarrow\frac{1}{7}x=\frac{2}{7}\Leftrightarrow x=2\)
+)\(-\frac{1}{5}x+\frac{3}{5}=0\Leftrightarrow-\frac{1}{5}x=-\frac{3}{5}\Leftrightarrow x=3\)
+)\(\frac{1}{3}x+\frac{4}{3}=0\Leftrightarrow\frac{1}{3}x=-\frac{4}{3}\Leftrightarrow x=-4\)
c, \(\frac{1}{2}x-\frac{11}{15}:\frac{33}{35}=-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}x-\frac{7}{9}=-\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{2}x=\frac{4}{9}\)
\(\Leftrightarrow x=\frac{8}{9}\)
NV
17 tháng 7 2016
a/ \(\frac{1}{6}x+\frac{1}{10}-\frac{4}{15}x+1=0\)
\(\Rightarrow-\frac{1}{10}x=-\frac{11}{10}\)
\(\Rightarrow x=11\)
b/ \(\left(\frac{1}{7}x-\frac{2}{7}\right)\left(-\frac{1}{5}x+\frac{3}{5}\right)\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
\(\Rightarrow\frac{1}{7}x-\frac{2}{7}=0\Rightarrow\frac{1}{7}x=\frac{2}{7}\Rightarrow x=2\)
hoặc \(-\frac{1}{5}x+\frac{3}{5}=0\Rightarrow-\frac{1}{5}x=-\frac{3}{5}\Rightarrow x=3\)
hoặc \(\frac{1}{3}x+\frac{4}{3}=0\Rightarrow\frac{1}{3}x=-\frac{4}{3}\Rightarrow x=-4\)
Vậy x = 2, x = 3, x = -4
c/ \(\frac{1}{2}x-\frac{11}{15}:\frac{33}{35}=-\frac{1}{3}\)
\(\Rightarrow\frac{1}{2}x-\frac{7}{9}=-\frac{1}{3}\)
\(\Rightarrow\frac{1}{2}x=\frac{4}{9}\Rightarrow x=\frac{8}{9}\)
Vậy x = 8/9
\(\frac{x}{15}=\frac{3}{5}+\frac{-2}{3}\)
\(\frac{x}{15}=\frac{9}{15}+\frac{-10}{15}\)
\(\frac{x}{15}=\frac{-1}{15}\)
\(=>x=-1\)
\(\frac{x}{15}=\frac{3}{5}+\frac{-2}{3}\)
\(\frac{x}{15}=\frac{-1}{15}\)
\(\Rightarrow15x=-15\)
\(x=-15:15\)
\(x=-1\)
Vậy x=1