bai 1xac dinh dau cua c ,biet rang 2a\(^3\)bc trai dau voi -3a\(^5\)b\(^3\)c\(^2\)bai 2cho day ti so bang nhau \(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)tinh gia tri bieu thuc m...
Đọc tiếp
bai 1
xac dinh dau cua c ,biet rang 2a\(^3\)bc trai dau voi -3a\(^5\)b\(^3\)c\(^2\)
bai 2
cho day ti so bang nhau
\(\frac{2a+b+c+d}{a}=\frac{a+2b+c+d}{b}=\frac{a+b+2c+d}{c}=\frac{a+b+c+2d}{d}\)
tinh gia tri bieu thuc m voi
m=\(\frac{a+b}{c+d}=\frac{b+c}{d+a}=\frac{c+d}{a+b}=\frac{d+a}{b+c}\)
