tim so nguyen x biet:
a, 23-x=19-(-12)
b, x-7=(-2)-8
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
b: \(\left(2x+1\right)^2=25\)
=>\(\left[{}\begin{matrix}2x+1=5\\2x+1=-5\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}2x=4\\2x=-6\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)
c: \(\left(1-3x\right)^3=64\)
=>\(\left(1-3x\right)^3=4^3\)
=>1-3x=4
=>3x=1-4=-3
=>x=-3/3=-1
d: \(\left(4-x\right)^3=-27\)
=>\(\left(4-x\right)^3=\left(-3\right)^3\)
=>4-x=-3
=>x=4+3=7
e: \(x^2-5x=0\)
=>\(x\left(x-5\right)=0\)
=>\(\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
\(A=\left(\frac{1}{2}-1\right)\left(\frac{1}{3}-1\right)\left(\frac{1}{4}-1\right)...\left(\frac{1}{2013}-1\right)\)
\(-A=\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2013}\right)\)
\(-A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{2012}{2013}\)
\(-A=\frac{1}{2013}\)
\(A=\frac{-1}{2013}\)
a, 7-x=8-(-7)
=> 7-x=15
=> x= 7-15
=> x=-8
b, x-8=-3+(-8)
=> x-8=-11
=> x=-11+8
=> x=-3
\(a,23-x=19-\left(-21\right)\)
\(23-x=19+21\)
\(23-x=40\)
\(x=23-40\)
\(x=-17\)
Vậy \(x\in\left\{-17\right\}\)
\(b,x-7=\left(-2\right)-8\)
\(x-7=\left(-2\right)+\left(-8\right)\)
\(x-7=-10\)
\(x=-10+7\)
\(x=-10-\left(-7\right)\)
\(x=-3\)
Vậy \(x\in\left\{-3\right\}\)
a)23-x=19-(-12)
=>23-x=31
x=23-31
x=-8
Vậy x=-8
b)x-7=(-2)-8
x-7=-10
x =(-10)+7
x =-3
Vậy x=-3