Tính: 4^5.9^4-10.6^9
2^10.3^8+6^8.28
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\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^{10}}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^{10}}\)
\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+3^2\right)}=-\dfrac{2}{10}=-\dfrac{1}{5}\)
\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^{10}}\)
\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^{10}}\)
\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^{10}.3^{10}}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8.\left(1+3^2\right)}\)
\(=\dfrac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.10}\)
\(=\dfrac{-2}{10}\)
\(=\dfrac{-1}{5}\)
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)
\(=\frac{-2}{6}=\frac{-1}{3}\)
\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)
\(=\dfrac{2.3^9.2^9-\left(2^2\right)^5.\left(3^2\right)^4}{2^{10}.3^7+3^7.2^7.2^3.5}\\ =\dfrac{2^{10}.3^9-2^{10}.3^8}{2^{10}.3^7+3^7.2^{10}.5}\\ =\dfrac{2^{10}.3^8\left(3-1\right)}{2^{10}.3^7\left(1+5\right)}\\ =\dfrac{3.2}{6}=\dfrac{6}{6}=1\)
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\(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}\)
\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.7}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9.5}{2^{10}.3^8+2^{10}.3^8.7}\)
\(=\frac{2^{10}.3^8\left(1-3.5\right)}{2^{10}.3^8\left(1+7\right)}=\frac{-14}{8}=-\frac{7}{4}\)
Vậy : \(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}=-\frac{7}{4}\)