Tìm 2 số tự nhiên a , b biết a+b =810 và ƯCLN (a , b) =45 và a nhỏ hơn b
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a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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Lưu ý: dấu"." là dấu nhân
Bài giải
Gọi m.45 = a và n.45 = b (m, n thuộc N*; m, n nguyên tố cùng nhau và m < n)
Theo đề bài:
a + b = m.45 + n.45 = (m + n).45 = 810
=> m + n = 810 ÷ 45 = 18
Vì m + n (m < n) nguyên tố cùng nhau
Nên m = 5, n = 13 hoặc m = 7, n = 11
Suy ra a = 5.45 = 225 và b = 13.45 = 585 hoặc a = 315 và b = 495
Vậy a = 225 và b = 585 hoặc a = 315 và b = 495
Bài toán này phải cảm ơn anh Đinh Tuấn Việt nhiều lắm