Tìm mẫu thức chung rồi quy đồng mẫu các phân thức sau :
a) \(\frac{2x-3y}{2xy};\frac{x+2y}{x}\)
b) \(\frac{2}{x^2-4x};\frac{x}{x^2-16}\)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
MB
1
23 tháng 1
\(\dfrac{1}{3x+3y}=\dfrac{1}{3\left(x+y\right)}=\dfrac{2\cdot\left(x+y\right)}{6\left(x+y\right)^2}\)
\(\dfrac{1}{2x+2y}=\dfrac{1}{2\left(x+y\right)}=\dfrac{3\left(x+y\right)}{6\left(x+y\right)^2}\)
\(\dfrac{1}{x^2+2xy+y^2}=\dfrac{1}{\left(x+y\right)^2}=\dfrac{6}{6\left(x+y\right)^2}\)
MB
1
22 tháng 1
\(\dfrac{1}{3x+xy}=\dfrac{1}{x\left(y+3\right)}=\dfrac{\left(x+y\right)^2}{x\left(y+3\right)\left(x+y\right)^2}\)
\(2x+2y=2\left(x+y\right)=\dfrac{2\left(x+y\right)\cdot x\left(y+3\right)\left(x+y\right)^2}{x\left(y+3\right)\left(x+y\right)^2}\)
\(\dfrac{1}{x^2+2xy+y^2}=\dfrac{3x+xy}{x\left(y+3\right)\left(x+y\right)^2}\)
28 tháng 7 2023
a: 1/x^2y=1/x^2y
3/xy=3x/x^2y
b: \(\dfrac{x}{x^2+2xy+y^2}=\dfrac{x}{\left(x+y\right)^2}\)
\(\dfrac{2x}{x^2+xy}=\dfrac{2}{x+y}=\dfrac{2x+2y}{\left(x+y\right)^2}\)
TN
18 tháng 11 2018
Tìm MTC: \(x^3-1=\left(x-1\right)\left(x^2+x+1\right)\)
Nên \(MTC=\left(x-1\right)\left(x^2+x+1\right)\)
Nhân tử phụ:
\(\left(x^3-1\right)\div\left(x^3-1\right)=1\)
\(\left(x-1\right)\left(x^2+x+1\right)\div\left(x^2+x+1\right)=x-1\)
\(\left(x-1\right)\left(x^2+x+1\right)\div1=\left(x-1\right)\left(x^2+x+1\right)\)
Quy đồng:
\(\frac{4x^2-3x+5}{x^3-1}=\frac{4x^2-3x+5}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(\frac{1-2x}{x^2+x+1}=\frac{\left(x-1\right)\left(1-2x\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)
\(-2=\frac{-2\left(x^3-1\right)}{\left(x-1\right)\left(x^2+x+1\right)}\)
7 tháng 12 2021
Bài 2:
a: \(\dfrac{1}{2x^3y}=\dfrac{6yz^3}{12x^3y^2z^3}\)
\(\dfrac{2}{3xy^2z^3}=\dfrac{2\cdot4x^2}{12x^3y^2z^3}=\dfrac{8x^2}{12x^3y^2z^3}\)
1 tháng 7 2017
MTC : \(150\left(x-2\right)\left(x-3\right)\)
\(\frac{5}{2x-4}=\frac{5}{2\left(x-2\right)}=\frac{5.3.\left(-25\right)\left(x-3\right)}{2.3.\left(-25\right)\left(x-2\right)\left(x-3\right)}=\frac{375\left(x-3\right)}{150\left(x-2\right)\left(x-3\right)}\)
\(\frac{z}{3x-9}=\frac{z}{3\left(x-3\right)}=\frac{z.2.\left(-25\right).\left(x-2\right)}{3.2.\left(-25\right)\left(x-3\right)\left(x-2\right)}=\frac{-50z\left(x-2\right)}{150\left(x-2\right)\left(x-3\right)}\)
\(\frac{7}{50-25x}=\frac{7}{-25\left(x-2\right)}=\frac{7.2.3.\left(x-3\right)}{-25.2.3\left(x-2\right)\left(x-3\right)}=\frac{42\left(x-3\right)}{150\left(x-2\right)\left(x-3\right)}\)
30 tháng 6 2023
i: MTC=(x-1)(x^2+1)
\(\dfrac{1}{x-1}=\dfrac{x^2+1}{\left(x-1\right)\left(x^2+1\right)}\)
\(\dfrac{2x}{x^3-x^2+x-1}=\dfrac{2x}{\left(x-1\right)\left(x^2+1\right)}\)
k: MTC=2(3x+1)(3x-1)
\(\dfrac{3x-1}{6x+2}=\dfrac{3x-1}{2\left(3x+1\right)}=\dfrac{\left(3x-1\right)^2}{2\left(3x+1\right)\left(3x-1\right)}\)
\(\dfrac{3x+1}{2-6x}=\dfrac{-\left(3x+1\right)}{2\left(3x-1\right)}=\dfrac{-\left(3x+1\right)^2}{2\left(3x-1\right)\left(3x+1\right)}\)
\(\dfrac{6x}{9x^2-1}=\dfrac{12x}{2\left(3x-1\right)\left(3x+1\right)}\)
a) MTC: 2xy
Quy đồng: \(\frac{2x-3y}{2xy}\) giữ nguyên
\(\frac{x+2y}{x}=\frac{2y\left(x+2y\right)}{2xy}=\frac{2xy+y^2}{2xy}\)
b) \(\frac{2}{x^2-4x}=\frac{2}{x\left(x-4\right)};\frac{x}{x^2-16}=\frac{x}{\left(x-4\right)\left(x+4\right)}\)
MTC: x (x-4)(x+4)
Quy đồng : \(\frac{2}{x\left(x-4\right)}=\frac{2\left(x+4\right)}{x\left(x-4\right)\left(x+4\right)}=\frac{2x+8}{x\left(x-4\right)\left(x+4\right)}\)
\(\frac{x}{\left(x+4\right)\left(x-4\right)}=\frac{x^2}{x\left(x-4\right)\left(x+4\right)}\)
Học tốt nhé ^3^